Implementing a counter using xslt

Question

I have this xml

<?xml version="1.0" encoding="UTF-8"?>
<Input>   
<Properties>
  <Type Name="Type1">
    <Property NAME="Prop1"/>
    <Property NAME="Prop2"/>
    <Property NAME="Prop3"/>
  </Type>
  <Type Name="Type2">
    <Property NAME="Prop4"/>
    <Property NAME="Prop5"/>
  </Type>
  <Type Name="Type3">
    <Property NAME="Prop6"/>
  </Type>
  <Type Name="Type4">
    <Property NAME="Prop7"/>
    <Property NAME="Prop8"/>
  </Type>
  <Type Name="Type5">
    <Property NAME="Prop9"/>
  </Type>
</Properties>
 </Input>

I need to implement a counter using xslt that will give me the total Property count under all types (in this case 9 ). Can it be done in xslt?

Jens · Accepted Answer · 2013-01-14 14:09:40Z

1

I need to implement a counter using xslt that will give me the total Property count under all types (in this case 9 ).

No, you don't need to implement a counter.

Just use:

count(/*/*/Type/Property)

To answer your next question:

Can it be done in xslt?

No, mutable variables are not possible in a functional language (a category to which XSLT belongs) -- by definition. And having mutable variables is not necessary.

Any problem that can be solved in an imperative way (with mutable variables), can also be solved in a functional way -- without using mutable variables.

edited Jan 14, 2013 at 14:09

Jens

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answered Jan 14, 2013 at 14:05

Dimitre Novatchev

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2 Comments

MartinKahn Over a year ago

Thanks @Dimitre. I will have to get started with the concepts of functional language.

Dimitre Novatchev Over a year ago

@MartinKahn, You are welcome. I recommend some of the books on XSLT and XPath contained in this answer: stackoverflow.com/a/341589/36305

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