Tkinter Lambda Button

Question

 from Tkinter import *
 import os

 ALL = N+S+W+E

 class Application(Frame):
def __init__(self, master=None):
    Frame.__init__(self, master)
    self.master.rowconfigure(0, weight=1)
    self.master.columnconfigure(0, weight=1)
    self.grid(sticky=ALL)

    for r in range(2):
        self.rowconfigure(r, weight=1)

        names = {0:'RED', 1:'BLUE', 2:'GREEN', 3:'BLACK', 4:'OPEN'}    
    for c, colname in enumerate(names):
        name = names[c]
        self.columnconfigure(c, weight=1)
        if colname < 4:
            Button(self, text=name, command = lambda x = name:  self.setcolor(x)).grid(row=2, column=c, sticky=ALL)
        else:
            Button(self ,width =30, text=name, command=self.doFileOpen).grid(row=2,column=c,sticky=ALL)  

    Frame1 = Frame(self, bg="red")
    Frame1.grid(row = 0, column = 0, rowspan = 1, columnspan = 2, sticky = ALL)
    Frame1.bind("<Button-1>", self.handler_1)
    Frame2 = Frame(self, bg="yellow")
    Frame2.grid(row = 1, column = 0, rowspan = 1, columnspan = 2, sticky = ALL)
    Frame2.bind("<Button-1>", self.handler_2)
    Frame3 = Frame(self)
    Frame3.grid(row = 0, column = 2, rowspan = 2, columnspan = 3, sticky = ALL)
    self.text_in = Entry(Frame3)
    self.output = Text(Frame3)
    self.text_in.pack(fill = X, expand=False)
    self.output.pack(fill = BOTH, expand=True)


def handler_1(event):
        print("clicked Frame 1 at", event.x, event.y)

def handler_2(event):
        print("clicked Frame 2 at", event.x, event.y)

def doFileOpen(self):
    eText = self.text_in.get()
    self.output.delete(1.0,END)
    self.output.insert(1.0, eText)

def setcolor(self,bname):



 root = Tk()
 app = Application(master=root)
 app.mainloop()

I am trying to get a setcolor definition to be called when I push one of the buttons <4. I am having an issue writing the set color definition. what is the best way to once I push the button change the color of the text in the text box that is gather from the entry box? When I click the "RED" box the text becomes red, "BLUE" becomes blue etc.

Do I need to call again dofileopen or can I just change the color after the fact?

Are you wanting to only change the color for part of the text in self.output, or change the color of all of the text? — Bryan Oakley
– Bryan Oakley, Commented Jan 14, 2013 at 16:39

TankorSmash · Accepted Answer · 2013-01-14 16:41:03Z

1

I'm not sure I understand correctly, but you're asking how to write the setcolor function so that it takes a color, and then sets the color of the appropriate text box? You could do something like:

def setcolor(self,bname):
    if bname == "RED": #or 1, can't tell how you've written it
        self.text_in.config(foreground = RED) #I think that's how colors work in tkinter
    elif bname == "BLUE":
        self.text_in.config(foreground = BLUE)
    #etc etc

It assumes self has the Entry you're wanting to change.

answered Jan 14, 2013 at 16:41

TankorSmash

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Trying_hard Over a year ago

I ended up using def setcolor(self,bname): self.output.config(foreground = bname) but I just shortened your answer thanks the config works great. I was thinking I had to reapply the dofileopen def.

Bryan Oakley · Accepted Answer · 2013-01-14 16:42:04Z

1

All Tkinter widgets have a configure method which lets you change any of the options associated with that widget. For example, to change the foreground color of a widget you would do this:

self.output.configure(foreground="red")

For text widgets, you can change the attributes of a range of characters by configuring a tag, then adding that tag to a range of text. For example:

self.output.tag_configure("tag1", foreground="red")
...
self.output.tag_add("tag1", 1.0, 2.0)

answered Jan 14, 2013 at 16:42

Bryan Oakley

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