How can something like the following be done in a PHP script?
code{
$result1 = task1() or break;
$result2 = task2() or break;
}
common_code();
exit();
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3 Answers
From the PHP help doco you can specify a function that is called after exit() but before the script ends.
Feel free to check the doco for more info https://www.php.net/manual/en/function.register-shutdown-function.php
<?php
function shutdown()
{
// This is our shutdown function, in
// here we can do any last operations
// before the script is complete.
echo 'Script executed with success', PHP_EOL;
}
register_shutdown_function('shutdown');
?>
Comments
if you use OOP then you could put the code you want to execute on exit into the destructor of your class.
class example{
function __destruct(){
echo "Exiting";
}
}
Comments
Your example is probably too simplistic, as it can easily be re-written as follows:
if($result1 = task1()) {
$result2 = task2();
}
common_code();
exit;
Perhaps you are trying to build flow-control like this:
do {
$result1 = task1() or break;
$result2 = task2() or break;
$result3 = task3() or break;
$result4 = task4() or break;
// etc
} while(false);
common_code();
exit;
You can also use a switch():
switch(false) {
case $result1 = task1(): break;
case $result2 = task2(): break;
case $result3 = task3(): break;
case $result4 = task4(): break;
}
common_code();
exit;
Or in PHP 5.3 you can use goto:
if(!$result1 = task1()) goto common;
if(!$result2 = task2()) goto common;
if(!$result3 = task3()) goto common;
if(!$result4 = task4()) goto common;
common:
echo "common code\n";
exit;
