Preview image using Fileupload asp.net mvc and Jquery

Question

I am trying to preview an image that the user is trying to upload. This is the code i am using.This is working fine in all major browsers, but i am wondering if there is a better way to achieve this without using session(even though i am clearing the session ) ? I don't want to use Flash.

   @using (Html.BeginForm("UploadImage", "Home", FormMethod.Post, new { id = "fileuploadform", @enctype = "multipart/form-data" }))
    {
        <input id="fileupload" type="file" onchange="ChangeImage()" name="files" multiple>
        <div id="preview">
            <img src="#" id="imgThumbnail" alt="preview" />
        </div>

    }
            <script>
            $(function ChangeImage() {
                $('#fileuploadform').fileupload({
                    done: function (e, data) {
                        var d = new Date();
                        $('#imgThumbnail')[0].src = "/Home/ImageLoad?a=" + d.getTime();
                    }
                });
            });
        </script>

[HttpPost]
public ActionResult UploadImage(IEnumerable<HttpPostedFileBase> files, PostViewModel model)
{

    Session["ContentLength"] = Request.Files[0].ContentLength;
    Session["ContentType"] = Request.Files[0].ContentType;
    byte[] b = new byte[Request.Files[0].ContentLength];
    Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength);
    Session["ContentStream"] = b;
    return Content(Request.Files[0].ContentType + ";" + Request.Files[0].ContentLength);
}

   public ActionResult ImageLoad(int? id)
    {
        byte[] b = (byte[])Session["ContentStream"];
        int length = (int)Session["ContentLength"];
        string type = (string)Session["ContentType"];
        Session["ContentLength"] = null;
        Session["ContentType"] = null;
        Session["ContentStream"] = null;
        return File(b, type);
    }

Community · Accepted Answer · 2017-05-23 12:08:05Z

3

Have you tried this solution?

Preview an image before it is uploaded

This solution is purely client side, and does not needed to be uploaded to your server before preview. :)

edited May 23, 2017 at 12:08

CommunityBot

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answered Jan 21, 2013 at 1:59

Victor Soto

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Comments

Himanshu · Accepted Answer · 2014-12-30 08:10:38Z

1

You could improve your action's code in this way:

HttpPostedFileBase picFile = Request.Files["fileUpload"];
if (picFile != null && picFile.ContentLength > 0)
{
     byte[] pic = new byte[picFile.ContentLength];
     picFile.InputStream.Read(pic, 0, picFile.ContentLength);
     // you can use pic ....
}

edited Dec 30, 2014 at 8:10

Himanshu

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answered Dec 30, 2014 at 7:33

Ayoub

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Comments

vishpatel73 · Accepted Answer · 2019-08-21 06:50:29Z

Preview image using Fileupload Asp.Net C# MVC with Razor Framework and jQuery?

This will preview multiple files as thumbnail images at a time.

On View Asp.Net C# MVC with Razor Framework

<div class="form-group">
   @Html.LabelFor(model => model.ImageMedias)
   <div class="input-group">
      <div class="custom-file">
         @Html.TextBoxFor(model => model.ImageMedias, "", new { @class = "custom-file-input", @type = "file", @multiple = "multiple", @accept = ".jfif,.jpg,.jpeg,.png,.gif" })
         <label class="custom-file-label" for="InputFile">Choose file</label>
      </div>
   </div>
   @Html.ValidationMessageFor(model => model.ImageMedias)   
   <div id="divImageMediaPreview">
   </div>
</div>

Script

$("#ImageMedias").change(function () {
    if (typeof (FileReader) != "undefined") {
        var dvPreview = $("#divImageMediaPreview");
        dvPreview.html("");            
        $($(this)[0].files).each(function () {
            var file = $(this);                
                var reader = new FileReader();
                reader.onload = function (e) {
                    var img = $("<img />");
                    img.attr("style", "width: 150px; height:100px; padding: 10px");
                    img.attr("src", e.target.result);
                    dvPreview.append(img);
                }
                reader.readAsDataURL(file[0]);                
        });
    } else {
        alert("This browser does not support HTML5 FileReader.");
    }
});

I hope this will help.

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