How to dynamically get value attribute value of a row using XSLT

Question

I have to create one table using XSLT and CSS. The table should look like

                ID    FNAME
                 1    AA
                 2    BB

XML:

<students>
    <studentDetails  id="1" fname="AA"/>
    <studentDetails  id="2" fname="BB"/>
</students>

XSLT so far: I have traverse upto studentDetails and then

<td >
      <xsl:call-template name="zz">
      <xsl:with-param name="child-name" select="'id'"/>
      </xsl:call-template>
    </td>
     <xsl:template name="zz">
<xsl:param name="child-name"/>

<xsl:value-of select="*[name(@id) = $child-name]"/>//should print 1 and then 2 in next row

Can somebody suggest where i am going wrong?

Dewfy · Accepted Answer · 2009-09-18 10:58:23Z

5

At first don't pass "'id'" just use "id" At second = pattern * selects node, but you need attr (@*), so you need write:

<xsl:value-of select="@*[name()=$child-name]"/>

answered Sep 18, 2009 at 10:58

Dewfy

23.8k13 gold badges78 silver badges126 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Wondering Over a year ago

At first don't pass "'id'" just use "id" At second = pattern * selects node----sorry didnt get u, can u pls explain a bit.

Dewfy Over a year ago

students, studentDetails -it is elements, when you write XPath expression to code any of them you need use ''. id, fname are attributes to get to them use over XPath over '@' Instead of * or @* you can specify axes (see hacker response) attribute::* = @*

Michael Krelin - hacker · Accepted Answer · 2009-09-18 12:54:43Z

2

try

<xsl:value-of select="attribute::*[name() = $child-name]"/>

instead.

Edit: I have just read through Dewfy's answer. This is equivalent to what he proposed. Except for his "at first" part is an alternative to this, not something you have to in addition to changing xsl:value-of.

edited Sep 18, 2009 at 12:54

answered Sep 18, 2009 at 11:10

Michael Krelin - hacker

144k25 gold badges200 silver badges177 bronze badges

2 Comments

Wondering Over a year ago

whats the difference between <xsl:value-of select="@*[name()=$child-name]"/> and <xsl:value-of select="attribute::*[name() = $child-name]"/>

Michael Krelin - hacker Over a year ago

Wondering - none ;-) It's just that after reading the first sentence I assumed he's talking about different approach instead.

Collectives™ on Stack Overflow

How to dynamically get value attribute value of a row using XSLT

2 Answers 2

2 Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related