How to find the maximum number in a list using a loop?

Usually, you could just use

max(nums)

If you explicitly want to use a loop, try:

max_value = None
for n in nums:
    if max_value is None or n > max_value: max_value = n

Here you go...

nums = [14, 8, 9, 16, 3, 11, 5]

big = max(nums)
spot = nums.index(big)

This would be the Pythonic way of achieving this. If you want to use a loop, then loop with the current max value and check if each element is larger, and if so, assign to the current max.

nums = [14, 8, 9, 16, 3, 11, 5]

big = None

spot = None

for i, v in enumerate(nums):
    if big is None or v > big:
         big = v
         spot = i

Python already has built in function for this kind of requirement.

list = [3,8,2,9]
max_number = max(list)
print (max_number) # it will print 9 as big number

however if you find the max number with the classic vay you can use loops.

list = [3,8,2,9]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print (current_max_number) #it will display 9 as big number

Why not simply using the built-in max() function:

>>> m = max(nums)

By the way, some answers to similar questions might be useful:

• Pythonic way to find maximum value and its index in a list?
• How to find all positions of the maximum value in a list?

To address your second question, you can use a for loop:

for i in range(len(list)):
    # do whatever

You should note that range() can have 3 arguments: start, end, and step. Start is what number to start with (if not supplied, it is 0); start is inclusive.. End is where to end at (this has to be give); end is exclusive: if you do range(100), it will give you 0-99. Step is also optional, it means what interval to use. If step is not provided, it will be 1. For example:

>>> x = range(10, 100, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95] # note that it does not hit 100

Since end is exclusive, to include 100, we could do:

>>> x = range(10, 101, 5) # start at 10, end at 101, and use an interval of 5
>>> x
[10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100] # note that it does hit 100

For the Max in List Code HS I've managed to get most of the auto grader to work for me using this code:

list = [-3,-8,-2,0]

current_max_number = list[0]
for number in list:
    if number>current_max_number:
        current_max_number = number

print current_max_number

def max_int_in_list():
    print "Here"

I'm not sure where the max_int_in_list goes though. It needs to have exactly 1 parameter.

To print the Index of the largest number in a list.

numbers = [1,2,3,4,5,6,9]

N = 0
for num in range(len(numbers)) :
  if numbers[num] > N :
    N = numbers[num]
print(numbers.index(N))

student_scores[1,2,3,4,5,6,7,8,9]

max=student_scores[0]
for n in range(0,len(student_scores)):
  if student_scores[n]>=max:
    max=student_scores[n]
print(max)
# using for loop to go through all items in the list and assign the biggest value to a variable, which was defined as max.

min=student_scores[0]
for n in range(0,len(student_scores)):
  if student_scores[n]<=min:
    min=student_scores[n]
print(min)
# using for loop to go through all items in the list and assign the smallest value to a variable, which was defined as min.

Note: the above code is to pick up the max and min by using for loop, which can be commonly used in other programming languages as well. However, the max() and min() functions are the easiest way to use in Python to get the same results.

I would add this as a reference too. You can use the sort and then print the last number.

nums = [14, 8, 9, 16, 3, 11, 5]

nums.sort()
print("Highest number is: ", nums[-1])

scores = [12, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27,
          28, 29, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 31, 31, 37,
          56, 75, 23, 565]

# initialize highest to zero
highest = 0

for mark in scores:
    if highest < mark:
        highest = mark

print(mark)