Create a variable from array of bytes

Question

In PHP I have an array of bytes that I want to turn into a single variable.

$bytes = array(0x12, 0x8D, 0x9D, 0x40, 0x09, 0x64, 0x5A, 0x6E);

I figured I could create a string like so:

$string = chr(0x12).chr(0x8D)......;

but that seems hacky.

Any suggestions?

I want one variable to contain all the bytes, so I can pass it to another function (mcrypt stuff). — Lance Rushing
– Lance Rushing, Commented Sep 18, 2009 at 19:01

dnagirl · Accepted Answer · 2009-09-18 19:21:45Z

1

$string=implode('',array_map('chr',array(0x8D, 0x9D, 0x40, 0x09, 0x64, 0x5A, 0x6E)));

echo $$string; //given that you also have a variable named whatever the bytecode translates to.

edited Sep 18, 2009 at 19:21

answered Sep 18, 2009 at 18:29

dnagirl

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Lance Rushing · Accepted Answer · 2009-09-18 19:14:32Z

0

I ended doing the same thing as dna girl, but more verbose.

Also becaue the array is coming from an ini file, the array not being recognized as a hex values. so I added an intval().

function getInitializationVector() {
    $ini = parse_ini_file('foo.ini');
    $stringVector = explode(',', $ini['initialization_vector'] );
    $iv = '';
    foreach($stringVector as $theByte) {
        $iv .= chr(intval($theByte, 16));
    }
    return $iv;
}

foo.ini :

initialization_vector=0x8D,0x9D,0x40,0x09,0x64,0x5A,0x6E,0xD4

p.s. You shouldn't need to store your IVs if you pad correctly. (but that is another story...)

answered Sep 18, 2009 at 19:14

Lance Rushing

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