How to loop through HTML5 multiple file upload?

Question

I have used the form below to upload multiple images to my server.

<form name="addimageForm" id="addimageForm" method="post" action="" enctype="multipart/form-data">              
    Gallery Image: 
    <input name="image_name[]" type="file" id="image_name" multiple="true">
    <input type="submit" name="addCatImage"/>
</form>

But I am confused how I should loop through it so that I can insert multiple images in my database. I used the code below, and when I run it, even when I select a image, 4 rows are inserted in my table. I think it is inserting all of the array fields(name, size, tmp_name). How can i solve the problem?

foreach ($_FILES[image_name] as $file) {
    $access->uploadSubCatImages();
}

user217782 · Accepted Answer · 2013-01-22 22:18:57Z

1

PHP makes the attributes themselves arrays. Yeah, I don't know who decided that.

// PHP does this:
$_FILES['image_name']['name'] = array('file1', 'file2', 'file'3);
$_FILES['image_name']['type'] = array('...', ...);

http://www.php.net/manual/en/features.file-upload.multiple.php

answered Jan 22, 2013 at 22:18

user217782

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Khanal · Accepted Answer · 2013-01-22 22:22:28Z

0

$_FILES is multidimensional. With the syntax that you used, the Filenames would be accessible in

$_FILES['image_name']['name'][0] # for the first one
$_FILES['image_name']['name'][1] # for the second one

and so on. Here is a link for reference Uploading Multiple Files

answered Jan 22, 2013 at 22:22

Khanal

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Comments

hek2mgl · Accepted Answer · 2013-01-22 22:32:43Z

0

First, the index to the $_FILES array is a string. Although will PHP 'eat' it and just throw a E_NOTICE, you should not do it. Use 'image_name' instead. (note the quotes)

Also the array structure may be different from what you've exptected. The following will loop trough the filen ames for example:

foreach ($_FILES['image_name']['name'] as $filename) {
    // do work here
}

Please refer to the documentation on $_FILES and especially this doc page.

edited Jan 22, 2013 at 22:32

answered Jan 22, 2013 at 22:15

hek2mgl

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3 Comments

user217782 Over a year ago

FYI, unquoted identifiers are interpreted as strings by PHP, with an E_NOTICE.

anon Over a year ago

@Rygu To be more specific, they're considered undefined constants, and PHP handles the error by interpreting the constant name as its value. This may change in a future version, so you should not rely on this.

user217782 Over a year ago

@AgentConundrum Thanks for the precise explanation. Indeed, one should not rely on it.

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