JQuery, have problems using variable as a selector

Question

I was given these set of practice instructions:

Write a selector which finds the UL within the tasks div and store this into a variable named task_list.

    var task_list = $('div#tasks ul');

then the next one got me confused:

Write a second selector line which finds all children within task_list that have the class name completed. Store this into a variable named all_completed. Use the detach() method. Call detach() on your all_completed variable.

     var all_completed = $(task_list).children('li.completed').detach();

or

   $(all_completed).detach(task_list);

Can someone please help me? Is this asking me to create a variable and use it as a selector in jQuery? If so, how do I do this??

I think your first version should work.

Barmar
– Barmar

2013-01-24 02:43:05 +00:00
Commented Jan 24, 2013 at 2:43 — Barmar
– Barmar, Commented Jan 24, 2013 at 2:43

John Koerner · Accepted Answer · 2013-01-24 02:37:08Z

4

task_list is already a jquery object, you don't need to re-jquery (is that a term?) it.

var all_completed = task_list.children('li.completed').detach();

answered Jan 24, 2013 at 2:37

John Koerner

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3 Comments

Barmar Over a year ago

I think jQuery determines pretty quickly that its argument is already a jQuery object, and just returns it. So there's little harm in re-jquerying.

KGKG Over a year ago

I'm not understanding how task_list is already jQuery-ied.... Is it because I assigned it a jQuery statement? I thought making a jQuery variable was done $variable = ('variablenowjQuery');??

John Koerner Over a year ago

When you $(".anything") you are creating a jquery object using the selector, in this case .anything

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