php get variable $_get

Question

userfile.php:

<form action="userrename.php" method="get">
      <input type="hidden" name="rename" value="<?= $filecode?>">
      <input type="submit" name="rename" id="bdelete" value="Rename"><br><br>
</form>

When I click rename button it is get: userrename.php?rename=pev8nERsJolwrCHyfQZujI1QHMDQHQX6V0ZMtQhsDi1aRgPeJsR&rename=rename

username.php:

<?php 
if(empty($_GET['rename'])) 
    echo "No GET variables"; 
else 
    echo $_GET['rename']; //here result is : rename
?>

I must get only this pev8nERsJolwrCHyfQZujI1QHMDQHQX6V0ZMtQhsDi1aRgPeJsR not rename in if statement. How I can do that any one has idei or know I am confused about that

farmer1992 · Accepted Answer · 2013-01-26 14:26:13Z

4

remove name of

<input type="submit" name="rename" id="bdelete" value="Rename">

or change its name to name="xxxx"

answered Jan 26, 2013 at 14:26

farmer1992

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Comments

Mahakala · Accepted Answer · 2013-01-26 14:34:55Z

1

Both your input for elements use same name (name="rename"), easiest solution is to change name of your submit input. If you have only 1 submit button on your form you can just remove the name attribute completely. Only elements with a name attribute will have their values passed when submitting a form, so if you remove it it is still a valid HTML and it's value won't be submitted..

answered Jan 26, 2013 at 14:34

Mahakala

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Comments

take · Accepted Answer · 2013-01-26 14:29:38Z

0

You can use following to have the filecode in GET and the rename value in POST:

<form action="userrename.php?rename=<?= $filecode?>" method="POST">
     <input type="submit" name="rename" id="bdelete" value="Rename"><br><br>
</form>

answered Jan 26, 2013 at 14:29

take

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1 Comment

Sven Over a year ago

The reason the value is not coming through is that the hidden input and the submit button have the same name! You are circumventing it by creating both a GET and a POST value of the same name - that's not good! Especially if the name of the submit button doesn't matter.

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