I need a regex matcher to find the pattern for a list consisting of a bunch of records
all of which end with a comma.
I want to, at the first occurrence of the comma insert beginning and end h1 tags.
I tried using (.*),
-
Can we see a sample input and output list?Explosion Pills– Explosion Pills2013-01-27 22:50:41 +00:00Commented Jan 27, 2013 at 22:50
-
Random Text In One Row, <- this is how every line looks. ends with a commaDino Excel– Dino Excel2013-01-27 22:51:37 +00:00Commented Jan 27, 2013 at 22:51
-
Just tried in notepad++, your regex works, did you enable the regex search in the bottom-left corner of the search box?BackSlash– BackSlash2013-01-27 22:52:16 +00:00Commented Jan 27, 2013 at 22:52
-
can you provide exactly what regex you used? (.*), <- ?Dino Excel– Dino Excel2013-01-27 22:54:29 +00:00Commented Jan 27, 2013 at 22:54
Add a comment
|
3 Answers
This should capture everything on a line up until and including the comma:
[^,]*?,
2 Comments
Dino Excel
But hey what if I want to end the line after the first occurrence of the comma? Because there are more commas on the same line, and I dont want them to be altered
woemler
This will depend on the regex implementation that you are using. The regex here by itself will start the the beginning of a string and match everything up tp and including the first comma. So long as your regex function does not globally match all occurrences, this will ignore all other comma-delimited text on the line.
You can use this regex:
^([^,]*),
This will locate the string before the first comma in a line. There is also capturing group that captures the text before the first comma for reference in replacement.
Comments
Try using either (.*?), or ([^,]+),. The former is preferred, but Notepad++ may not support it.
1 Comment
Dino Excel
But this only locates the comma... I need to locate the string before the comma.
