71

I need to create a hashmap with key as integer and it should hold multiple values of different data types. For example if the key is msg id and the values are

  1. message of type string
  2. timestamp of type time
  3. count of type integer
  4. version of type integer

Then how to store the values of different data type with a single key into the hashmap?

3
  • 9
    You need to create a class holding all that information, and than use a Map<Integer, YourClass> Commented Jan 30, 2013 at 8:14
  • 3
    If all your variables are of type Object then you could create it as Map<Integer, Object> Commented Feb 7, 2013 at 9:47
  • There are two ways this question can be read: (1) How to have each HashMap element represent a collection of data and (2) how create a HashMap wherein the elements are of nonuniform type. I believe that the intended meaning is #1, but I am grateful for the answers to #2. Commented Nov 5, 2020 at 23:16

5 Answers 5

63

If you don't have Your own Data Class, then you can design your map as follows

Map<Integer, Object> map=new HashMap<Integer, Object>();

Here don't forget to use "instanceof" operator while retrieving the values from MAP.

If you have your own Data class then then you can design your map as follows

Map<Integer, YourClassName> map=new HashMap<Integer, YourClassName>();

import java.util.Date;
import java.util.HashMap;
import java.util.Map;
import java.util.Set;


public class HashMapTest {
public static void main(String[] args) {
    Map<Integer,Demo> map=new HashMap<Integer, Demo>();
    Demo d1= new Demo(1,"hi",new Date(),1,1);
    Demo d2= new Demo(2,"this",new Date(),2,1);
    Demo d3= new Demo(3,"is",new Date(),3,1);
    Demo d4= new Demo(4,"mytest",new Date(),4,1);
    //adding values to map
    map.put(d1.getKey(), d1);
    map.put(d2.getKey(), d2);
    map.put(d3.getKey(), d3);
    map.put(d4.getKey(), d4);
    //retrieving values from map
    Set<Integer> keySet= map.keySet();
    for(int i:keySet){
        System.out.println(map.get(i));
    }
    //searching key on map
    System.out.println(map.containsKey(d1.getKey()));
    //searching value on map
    System.out.println(map.containsValue(d1));
}

}
class Demo{
    private int key;
    private String message;
    private Date time;
    private int count;
    private int version;

    public Demo(int key,String message, Date time, int count, int version){
        this.key=key;
        this.message = message;
        this.time = time;
        this.count = count;
        this.version = version;
    }
    public String getMessage() {
        return message;
    }
    public Date getTime() {
        return time;
    }
    public int getCount() {
        return count;
    }
    public int getVersion() {
        return version;
    }
    public int getKey() {
        return key;
    }
    @Override
    public String toString() {
        return "Demo [message=" + message + ", time=" + time
                + ", count=" + count + ", version=" + version + "]";
    }

}
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2 Comments

can u plz provide me with an example for creating the hashmap like below and adding and searching and retrieving values from it "Map<Integer, YourClassName> map=new HashMap<Integer, YourClassName>();"
Yep Sure.. please find the edited answer.. The example is only all about how to add,search, retrieve values in HashMap.
47

You have some variables that are different types in Java language like that:

 message of type string
 timestamp of type time
 count of type integer
 version of type integer

If you use a HashMap like:

HashMap<String,Object> yourHash = new HashMap<String,Object>();
yourHash.put("message","message");
yourHash.put("timestamp",timestamp);
yourHash.put("count ",count);
yourHash.put("version ",version);

If you want to use the yourHash:

for(String key : yourHash.keySet()){
  String message = (String) yourHash.get(key);
  Datetime timestamp= (Datetime) yourHash.get(key);
  int timestamp= (int) yourHash.get(key);
}

1 Comment

I didn't think to try casting to the datatypes, because the error I was seeing was "cannot cast type". Then I casted them, even though it said it "cannot cast type", and it worked. :')
20

Define a class to store your data first

public class YourDataClass {

    private String messageType;
    private Timestamp timestamp;
    private int count;
    private int version;

    // your get/setters
    ...........
}

And then initialize your map:

Map<Integer, YourDataClass> map = new HashMap<Integer, YourDataClass>();

2 Comments

Although correct, this answer defeats the whole purpose of the OPs question. The goal of putting these values into a Map object is precisely avoiding creating tons of classes, and having the flexibility of adding as many entries in the map as needed.
Meh. It answers the question as asked.
6

Create an object holding following properties with an appropriate name.

  1. message
  2. timestamp
  3. count
  4. version

and use this as a value in your map.

Also consider overriding the equals() and hashCode() method accordingly if you do not want object equality to be used for comparison (e.g. when inserting values into your map).

8 Comments

Good suggestion, but equals() and hashCode() are not important, as his keys will be Integer.
Agree, not necessary for using it as a value, but I guess he might want to compare the values once retrieved from the map. And second it's good practice. I would do it in any case.
I agree that it's good practice and upvoted your answer. But we have no clue what OP wants to do with those objects once he reads them from the map.
+1 for the first correct answer, but Drogba's answer is easier to read.
I also agree with @jlordo. If you draw attention to particular methods (e.g. equals()), you need to explain why this is important. Merely highlighting best practice will tend to bloat answers unnecessarily.
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5

Do simply like below....

HashMap<String,Object> yourHash = new HashMap<String,Object>();
yourHash.put(yourKey+"message","message");
yourHash.put(yourKey+"timestamp",timestamp);
yourHash.put(yourKey+"count ",count);
yourHash.put(yourKey+"version ",version);

typecast the value while getting back. For ex:

    int count = Integer.parseInt(yourHash.get(yourKey+"count"));
//or
int count = Integer.valueOf(yourHash.get(yourKey+"count"));
//or
int count = (Integer)yourHash.get(yourKey+"count"); //or (int)

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