I want to validate a string which donot have numeric characters.
If my string is "javaABC" then it must be validated If my string is "java1" then it must not be validated
I want to restrict all the integers.
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This kind of question can easily be answered by creating a small test program.Pat– Pat2009-09-23 10:58:23 +00:00Commented Sep 23, 2009 at 10:58
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5 Answers
Try this:
String Text = ...;
boolean HasNoNumber = Text.matches("^[^0-9]*$");
'^[^0-9]*$' = From Start(^) to end ($), there are ([...]) only non(^) number(0-9). You can use '\D' as other suggest too ... but this is easy to understand.
See more info here.
3 Comments
Brian Agnew
Perhaps it's easier for a regexp newbie to understand hasDigits = Text.matches("[0-9]") ?
Andrey Adamovich
"^\\D*$" is a shorter form ;)
Alan Moore
@Brian:
Text.matches("[0-9]") means "Text" consists of exactly one digit; you would need to say Text.matches("(?s).*[0-9].*") -- Java's funny that way. OTOH, @NawaMan's regex doesn't really need the anchors: Text.matches("[^0-9]*") or Text.matches("\\D*") work just fine.You can use this:
\D
"\D" matches non-digit characters.
Comments
More detail is here: http://java.sun.com/javase/6/docs/api/java/util/regex/Pattern.html
Comments
Here is one way that you can search for a digit in a String:
public boolean isValid(String stringToValidate) {
if(Pattern.compile("[0-9]").matcher(stringToValidate).find()) {
// The string is not valid.
return false;
}
// The string is valid.
return true;
}
Comments
The easiest to understand is probably matching for a single digit and if found fail, instead of creating a regexp that makes sure that all characters in the string are non-digits.
answered Sep 23, 2009 at 10:58
Thorbjørn Ravn Andersen
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