json_decode return json data

Question

Im just posting single data value like this '{'email':'[email protected]'}'

php file

$var = json_decode($_POST,true);
echo json_encode($var["email"]);

at this stage i just want to return the email address to get it working buts its giving me this error:

json_decode() expects parameter 1 to be string, array given in C:\wamp\www\buyme\include\getemailaddress.php on line 4

line 4 is the first line in my code

all i want to be able todo is access the email value and return it back in json_encode($var["email"])

You trying to pass an array($_POST) instead you need to password a simple string. '{'email':'[email protected]'}' — Raja
– Raja, Commented Feb 4, 2013 at 5:19

DiverseAndRemote.com · Accepted Answer · 2013-02-04 05:00:28Z

1

If I got you correctly and your posting a json string you can do:

$requestBody = @file_get_contents('php://input');
$var = json_decode($requestBody, true);
echo json_encode($var['email']);

edited Feb 4, 2013 at 5:00

answered Feb 4, 2013 at 4:54

DiverseAndRemote.com

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1 Comment

DiverseAndRemote.com Over a year ago

what returns null? $requestBody? $var? or $var['email']? You gotta be a little more specific

Nishu Tayal · Accepted Answer · 2013-02-04 05:14:22Z

0

As you can read in PHP Manual $_POST, $_POST contains values in associative array. As in manaul too, it is :

An associative array of variables passed to the current script via the HTTP POST method.

So if you are sending any json string from client-end in any variable, Use that variable to read that json string like this.

$var = json_decode($_POST['emaildata'],true);
echo json_encode($var["email"]);

Please check, if it works for you..

answered Feb 4, 2013 at 5:14

Nishu Tayal

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2 Comments

ONYX Over a year ago

how do i access the posted jason object do you know how you do this I getting confused or people re confusing me

Nishu Tayal Over a year ago

How are you posting data from client-end, can you please share that code chuck? And let me know if you also tried $_POST['variable-name'].. Here variable-name contains that json string.

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