Recursive decoding of URI component in python like javascript

Question

I have a encoded URI component "http://www.yelp.com/biz/carriage-house-caf%25C3%25A9-houston-2". I could able to convert this to "http://www.yelp.com/biz/carriage-house-café-houston-2" by applying decodeURIComponent function recursively as below

function recursiveDecodeURIComponent(uriComponent){
        try{
            var decodedURIComponent = decodeURIComponent(uriComponent);
            if(decodedURIComponent == uriComponent){
                return decodedURIComponent;
            }
            return recursiveDecodeURIComponent(decodedURIComponent);
        }catch(e){
            return uriComponent;
        }
    }
    console.log(recursiveDecodeURIComponent("http://www.yelp.com/biz/carriage-house-caf%25C3%25A9-houston-2"))

Outputs: "http://www.yelp.com/biz/carriage-house-café-houston-2".

I would like to get the same in python. I tried the following:

print urllib2.unquote(urllib2.unquote(urllib2.unquote("http://www.yelp.com/biz/carriage-house-caf%25C3%25A9-houston-2").decode("utf-8")))

but I got http://www.yelp.com/biz/carriage-house-cafÃ©-houston-2. Instead of Expected character é, I got 'Ã©' irrespective of any number of calling urllib2.unquote.

I am using python2.7.3, can anyone help me?

georg · Accepted Answer · 2013-02-05 08:35:18Z

1

I guess a simple loop should do the trick:

uri = "http://www.yelp.com/biz/carriage-house-caf%25C3%25A9-houston-2"

while True:
    dec = urllib2.unquote(uri)
    if dec == uri:
        break
    uri = dec

uri = uri.decode('utf8')
print '%r' % uri  
# u'http://www.yelp.com/biz/carriage-house-caf\xe9-houston-2'

edited Feb 5, 2013 at 8:35

answered Feb 5, 2013 at 8:16

georg

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1 Comment

Martin B. Over a year ago

my bad, I was just testing something else and got put off by mixed encoded/non-encoded unquoting.. nevermind :)

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