I need to get list of elements all css attributes. How can I do that ?
4 Answers
Copying the source from SO1004475 - jQuery CSS plugin that returns computed style of element to pseudo clone that element? - Please follow link and upvote there if you find it useful.
It seems ridiculous, but this is probably your best option - makes .css() with no arguments get an object with all this stuff set.
jQuery.fn.css = (function(css2) {
return function() {
if (arguments.length) { return css2.apply(this, arguments); }
var attr = ['font-family','font-size','font-weight','font-style','color',
'text-transform','text-decoration','letter-spacing','word-spacing',
'line-height','text-align','vertical-align','direction','background-color',
'background-image','background-repeat','background-position',
'background-attachment','opacity','width','height','top','right','bottom',
'left','margin-top','margin-right','margin-bottom','margin-left',
'padding-top','padding-right','padding-bottom','padding-left',
'border-top-width','border-right-width','border-bottom-width',
'border-left-width','border-top-color','border-right-color',
'border-bottom-color','border-left-color','border-top-style',
'border-right-style','border-bottom-style','border-left-style','position',
'display','visibility','z-index','overflow-x','overflow-y','white-space',
'clip','float','clear','cursor','list-style-image','list-style-position',
'list-style-type','marker-offset'];
var len = attr.length, obj = {};
for (var i = 0; i < len; i++) {
obj[attr[i]] = css2.call(this, attr[i]);
}
return obj;
};
})(jQuery.fn.css);
Note that this doesn't capture all possible CSS properties, particularly new ones for CSS3. Here is a list of all standard CSS and stable CSS3 properties, and here's one of hyphen-prefixed vendor-specific properties (such as -moz-border-start). If you really want all of them, you can glean them from there.
4 Comments
gnarf
Agreed - but I think its what the OP was asking for.
Justin Morgan
Edited to avoid polluting the
jQuery.fn namespace with a css2 function. Otherwise, this is great stuff.
mgol
@gnarf Note that jQuery since 1.9 can take an array of properies in its css method so the loop is not needed there.
Matthew Carpenter
nice script, i see no box-shadow?
As of jQuery 1.8, you can do:
$( "#yourElement" ).css( "cssText" );
Which uses the underlying window.getComputedStyle( element ).cssText. That's the simplest way.
3 Comments
Mike Sherov
@EJTH I'm the author of that code inside jQuery ;-)
EJTH
Thanks! You helped me solve the problem of moving stuff to a certain container in the dom without any styling getting lost! :-) I use it for some pet project, make a HTML page fall apart with box2d...
Leviscus Tempris
WOW! I love this! Simply the best way if you want a dump of every CSS property in existence!
For inline styles:
var styles = $("#someelement").attr("style");
From there, you should be able to split this string if you need to loop the styles.
To check individual styles, check the docs:
$("#div1).css("background-color");
will return the background color property of an element with id div1.
Sorry, I don't know a way to get all the CSS attributes using jQuery.
document.defaultView.getComputedStyle(document.body, '')got from stackoverflow.com/questions/2614963/…