I have a text file which contains a list of values:
ASDSAV
ASDSAD
ASDFSA
and need to get
ASDSAV 7
ASDSAD 7
ASDFSA 7
i.e. join it with a file that is just one column of 7s (which can be easily achieved with paste)
7
7
7
Is there easy command to create this file of 7s?
awk '{print $0, "7"} ' inputfile > newfile
There is no need for a separate file of 7's
The question is actually how to create a file with a list of sevens.
You can use some coreutils:
printf '7\n%.0s' $(seq $(wc -l < file)) > output.txt
or awk:
awk '{ print "7" > "output.txt" }' file
or sed:
sed 's/.*/7/' file > output.txt
awk '{print $1 " 7"}' temp.dat; where temp.dat is your original file.
ALMIGHTY SED
sed -e "s/$/7/" f1 > f2
MAY YOUR AWKS CRUMBLE BEFORE HIS FEET
side note: if u want to tab the 7 out in sed it would be
sed -e "s/$/<ctrl+v><tab>7/" f1 > f2
The yes command provides an unlimited supply of its argument:
yes 7 | head -n $(wc -l < file.txt) | paste file.txt -
(It's good to know about yes, but in this case it's a bit clunky. paste auto-extends shorter input files with empty lines, and the yes-supplied standard input is infinitely long without the head to limit it.)
