jQuery: checking if value is in array, if so, delete, if not, add

Question

I'm trying to check if there's a value in the array already. If the value does not exists in array, then it should be added into the array, if the value already exists, it should be deleted.

var selectArr = [];
$('.media-search').mouseenter(function(){
    var $this = $(this);
    $this.toggleClass('highlight');
}).mouseleave(function(){
    var $this = $(this);
    $this.toggleClass('highlight');

}).on('click',function(){
    var dataid = $(this).data('id');

    if(selectArry){ // need to somehow check if value (dataid) exists.
    selectArr.push(dataid); // adds the data into the array
    }else{
    // somehow remove the dataid value if exists in array already
    }


});

Guffa · Accepted Answer · 2013-02-09 01:42:38Z

36

Use the inArray method to look for a value, and the push and splice methods to add or remove items:

var idx = $.inArray(dataid, selectArr);
if (idx == -1) {
  selectArr.push(dataid);
} else {
  selectArr.splice(idx, 1);
}

answered Feb 9, 2013 at 1:42

Guffa

703k111 gold badges760 silver badges1k bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Banana · Accepted Answer · 2018-02-12 09:22:24Z

0

Simple JavaScript program to find and add/remove the value in the array

var myArray = ["cat","dog","mouse","rat","mouse","lion"]
var count = 0; // To keep a count of how many times the value is removed 
for(var i=0; i<myArray.length;i++) {
    //Here we are going to remove 'mouse'
    if(myArray[i] == "mouse") {
        myArray .splice(i,1);
        count = count + 1;
    }
}
//Count will be zero if no value is removed in the array
if(count == 0) {
    myArray .push("mouse"); //Add the value at last - use 'unshife' to add at beginning 
}

//Output
for(var i=0; i<myArray.length;i++) {
    console.log(myArray [i]); //Press F12 and click console in chrome to see output
}

edited Feb 12, 2018 at 9:22

Banana

2,4438 gold badges37 silver badges62 bronze badges

answered Feb 12, 2018 at 7:48

Muthukumar

6547 silver badges9 bronze badges

Comments

Hardeep Singh · Accepted Answer · 2019-11-12 07:27:00Z

  function AddingOffences() {

var sendingcountry = ary.filter((item) => {
  return (item.Offence.toLowerCase().indexOf($("#ddl_OffencesByLocation option:selected").val()) > -1);
})
if (sendingcountry == "") {

  if ($("#txtPriceByLocation").val() == "") {
    alert("Please select price")
  } else {



    $("#Div_OffenceListByLoction").append("<li id=" + $("#ddl_OffencesByLocation option:selected").val() + ">" + $("#ddl_OffencesByLocation option:selected").text() + "<span>" + $("#txtPriceByLocation").val() + " kr" + "</span><span onclick='RemoveOffence(" + $("#ddl_OffencesByLocation option:selected").val() + ")' > Remove</span></li>");
    pushToAry($("#ddl_OffencesByLocation option:selected").val(), $("#txtPriceByLocation").val());
  }
  } else {
    alert("Allready Exist");
  }

}

Collectives™ on Stack Overflow

jQuery: checking if value is in array, if so, delete, if not, add

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related