getting file name from for %%i variable

Question

I had a script that converts all mkvs in a folder to mp4s using ffmpeg. The downside is that it left the .mkv extension and just added .mp4 (eg: file.mkv.mkp4). I know %~n can be used to get a name without the extension, but I can't seem to figure it out.

Here's my original script:

for %%i IN (*.mkv) DO (ffmpeg -y -ss 00:00:00 -threads 6 -i "%%i" -vcodec copy -f mp4 -strict experimental -acodec aac -ab 128k -ac 2 "%%i.mp4")

Here's what I've tried:

for %%i IN (*.mkv) DO (ffmpeg -y -ss 00:00:00 -threads 6 -i "%~ni.mkv" -vcodec copy -f mp4 -strict experimental -acodec aac -ab 128k -ac 2 "%~ni.mp4")

Ansgar Wiechers · Accepted Answer · 2015-03-19 19:50:22Z

6

Percent signs of loop variables must be doubled in batch scripts, so you have to use %%~ni instead of %~ni. See the Examples section in the documentation.

edited Mar 19, 2015 at 19:50

answered Feb 10, 2013 at 0:05

Ansgar Wiechers

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2 Comments

MarcusJ Over a year ago

That link is dead, the proper location is: technet.microsoft.com/en-us/library/bb490869.aspx

Ansgar Wiechers Over a year ago

@MarcusJ Actually it's technet.microsoft.com/en-us/library/bb490909.aspx, but thanks for the heads-up. Fixed.

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