I have a url:
http://www.abc.com?refurl=/english/info/test.aspx?form=1&h=test&s=AB
If I use
Request.QueryString["refurl"
but gives me
/english/info/test.aspx?form=1
instead I need full url
/english/info/test.aspx?form=1&h=test&s=AB
4 Answers
Fix the problem, and the problem is that you place a full url as parameter refurl with out encoding it.
So where you create that url string use the UrlEncode() function, eg:
"http://www.abc.com?refurl=" + Server.UrlEncode(ReturnUrlParam)
where
ReturnUrlParam="/english/info/test.aspx?form=1&h=test&s=AB";
Comments
For that particular case you shouldn't use QueryString, (since your query string contains three parameters,) instead use Uri class, and Uri.Query will give you the required result.
Uri uri = new Uri(@"http://www.abc.com?refurl=/english/info/test.aspx?form=1&h=test&s=AB");
string query = uri.Query;
Which will give you :
?refurl=/english/info/test.aspx?form=1&h=test&s=AB
Later you can remove ?refurl= to get the desired output.
I am pretty sure there is no direct way in the framework for your particular requirement, you have to implement that in your code and that too with string operations.
2 Comments
Evaldas Dzimanavicius
It would not work if you would send more parameters (not only refurl)
I had similar situation some time ago. I solved it by encoding refurl value. now my url looks similar to that one: http://www.abc.com?refurl=adsf45a4sdf8sf18as4f6as4fd
I have created 2 methods:
public string encode(string);
public string decode(string);
Before redirect or where you have your link, you simple encode the link and where you are reading it, decode before use:
Response.redirect(String.Format("http://www.abc.com?refurl={0}", encode(/english/info/test.aspx?form=1&h=test&s=AB));
And in the page that you are using refurl:
$refUrl = Request.QueryString["refurl"];
$refUrl = decode($refUrl);
EDIT:
encode/decode methods I actually have as extension methods, then for every string I can simply use string.encode() or string.decode().
1 Comment
Anna.P
you answer is also right. I am trying to use without encoding.
you should replace the & with &.
Comments
?that is not in the correct format - and because you make this, is better to fix that. You can fix by using theUrlEncodefunction, when you add a full url string