New to php: I have a simple array:
$people = array('Joe','Jane','Mike');
How do I output this into a list?
<ul>
<li>Joe</li>
<li>Jane</li>
<li>Mike</li>
</ul>
Any help or direction would be appreciated?
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This is basic PHP. Use a loop.John Conde– John Conde2013-02-11 14:44:57 +00:00Commented Feb 11, 2013 at 14:44
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php.net/foreachMarc B– Marc B2013-02-11 14:49:13 +00:00Commented Feb 11, 2013 at 14:49
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5 Answers
You can use implode() and print the list:
echo '<ul>';
echo '<li>' . implode( '</li><li>', $people) . '</li>';
echo '</ul>';
Note this would print an empty <li> for an empty list - You can add a check in to make sure the array isn't empty before producing any output (which you would need for any loop so you don't print an empty <ul></ul>).
if( count( $people) > 0) {
echo '<ul>';
echo '<li>' . implode( '</li><li>', $people) . '</li>';
echo '</ul>';
}
1 Comment
Captain Hypertext
I knew there had to be a concise way to do this.
Try:
echo '<ul>';
foreach($people as $p){
echo '<li>'.$p.'</li>';
}
echo '</ul>';
Comments
Try this:
echo "<ul>";
foreach(people as $person){
echo "<li>". $person ."</li>";
}
echo "</ul>";
Comments
You need to use loop to output array data as text.
There are multiple loops in PHP:
FOR
For will iterate $i (can be diferent variable and different change than iteration) and will end when the condition is not true anymore.
$people = array('Joe','Jane','Mike');
for($i=0; $i<count($people); $i++) { //end when $i is larger than amount of people
echo " <li>{$people[$i]}</li>\n";
}
FOREACH
Very useful for unordered arrays - this loop will give you all values in the array as variable you want:
$people = array('Joe','Jane','Mike');
foreach($people as $human) { //end when $i is larger than amount of people
echo " <li>$human</li>\n";
}
WHILE
Like FOR, loops while condition is met.
Comments
<?php
echo "<ul>";
foreach(array("test", "test2", "test3") as $string)) {
echo "<li>".$string."</li>"
}
echo "<ul>";
?>
