validate javascript expressions

Question

I have done a test for a gender expression -

function gender()
{
    var gender = document.form1.radio[0].checked;
    var gender1 = document.form1.radio[1].checked;  
        if(gender || gender1)
        {
        }
        else
        {
            errorMsg = errorMsg + "please select your gender\n" 
        }
}

but I would like to be able to write it so that there is no need for an empty positive outcome like this -

if ((alphabetic.test(fname)== false) || (alphabetic.test(lname)== false))
{
alertmsg = alertmsg + "Name should be in alphabets:" + "\n";
}

I am sorry if I appear to be very stupid, I am a complete beginner. any help would be appreciated, thanks

Please do not use checkboxes for gender input. It is not fair: intersexroadshow.blogspot.de/2012/02/… — Amberlamps
– Amberlamps, Commented Feb 15, 2013 at 17:23
I would also, for clarity, maybe name your variables after the actual gender as opposed to gender and gender1. Also a great programmer would account for the possibility of new genders :|. — lmortenson
– lmortenson, Commented Feb 15, 2013 at 17:23
I was told on my course that my testing code was too complex and that I should re-write it so there is no need for empty positive outcomes and that I should use the same testing method like the first and last name. I'm not sure what they mean — user2073133
– user2073133, Commented Feb 15, 2013 at 17:25

Andorbal · Accepted Answer · 2013-02-15 17:22:26Z

1

function gender()
{
var gender = document.form1.radio[0].checked;
var gender1 = document.form1.radio[1].checked;  
    if(!(gender || gender1))
    {
        errorMsg = errorMsg + "please select your gender\n" 
    }
}

answered Feb 15, 2013 at 17:22

Andorbal

8805 silver badges15 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

bfavaretto · Accepted Answer · 2013-02-15 17:22:32Z

0

If I understand correctly:

if(!gender && !gender1) {
    errorMsg = errorMsg + "please select your gender\n" 
}

answered Feb 15, 2013 at 17:22

bfavaretto

72k18 gold badges118 silver badges162 bronze badges

3 Comments

user2073133 Over a year ago

function gender() { var gender = document.form1.radio[0].checked; var gender1 = document.form1.radio[1].checked; if(!gender && !gender1) { errorMsg = errorMsg + "please select your gender\n" }

user2073133 Over a year ago

this would make sure they have selected at least one of the 2 radio buttons?

bfavaretto Over a year ago

@user2073133 Yes, it will. If none is selected, the final result will be true, and the error message will be appended. In any other case, the final result will be false.

Damium · Accepted Answer · 2013-02-15 17:28:02Z

0

Not really sure what you are trying to do but, try using the logical NOT "!":

function gender()
{
    var gender = document.form1.radio[0].checked;
    var gender1 = document.form1.radio[1].checked;  
    if !(gender || gender1)
    {
        errorMsg = errorMsg + "please select your gender\n" 
    }

}

answered Feb 15, 2013 at 17:28

Damium

645 bronze badges

1 Comment

user2073133 Over a year ago

I just need a test to check that at least one gender is selected. A Test that is better than my original one, thank you

Collectives™ on Stack Overflow

validate javascript expressions

3 Answers 3

Comments

3 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

3 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related