./build_binaries.sh: line 43: [: ==: unary operator expected
I have this line (line 43) in my bash script which looks correct to me, but it keeps throwing error.
if [ ${platform} == "macosx" ]; then
Error:
./foo.sh: line 43: [: ==: unary operator expected
This is on OSX.
The problem is that $platform is an empty string. The usual workaround is to put it in quotes:
if [ "${platform}" == "macosx" ]
Example:
$ unset x
$ [ $x == 3 ]
-bash: [: ==: unary operator expected
$ [ "$x" == "3" ]
$
One possibility is to use a single =. That's the classic notation. Some shells allow ==, but others do not.
Also, you should enclose the ${platform} in double quotes; I think that it is an empty string, and this is confusing things.
platform=
if [ $platform == mac ]; then echo hi; else echo lo; fi
if [ "$platform" == mac ]; then echo hi; else echo lo; fi
This produces the error you're seeing on the second line.
