PHP can I call unexistent function with call_user_func

Question

Here it what I want to do: I have an object

class TestObject {
      public function __call($name,$args){
        if($name == 'somemethod'){
          print "Yesssss!!!!!!";
        }
      }
}

than in code i'm calling this method like this:

$obj = new TestObject()
$obj->somemethod()  // should work according to http://www.php.net/manual/en/language.oop5.overloading.php#object.call
call_user_func(array('myobject','somemethod')) // this does not work!!!

Is there any way to get the last example to work?

Have you tried array($obj, 'somemethod');?

Pekka
– Pekka

2013-02-17 16:26:51 +00:00
Commented Feb 17, 2013 at 16:26 — Pekka
– Pekka, Commented Feb 17, 2013 at 16:26

Vatev · Accepted Answer · 2013-02-17 16:27:04Z

0

You can use

call_user_func(array($obj,'somemethod'));

or

$method = 'somemethod';
$obj->$method();

answered Feb 17, 2013 at 16:27

Vatev

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4 Comments

1099511627776 Over a year ago

call_user_func(array($obj,'somemethod')); - this wont call unexistent method

Vatev Over a year ago

It does call the '__call' method if it doesn't exist.

1099511627776 Over a year ago

$obj->$method(); - the problem is that I cannot use this type of calling. i need to use call_user_func

1099511627776 Over a year ago

Hmm, yes it does call __call method in test script.

sh03 · Accepted Answer · 2013-02-17 16:26:17Z

0

$obj_name = 'myobject';
$method_name = 'somemethod';
${$obj_name}->${$method->name()};

answered Feb 17, 2013 at 16:26

sh03

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