Splitting a MySQL Query result into an multidimensional-array

Question

I have the following result from a MySQL query with two joins.

Array ( 
[0] => Array ( [place_id] => 1 [place] => Berlin [lat] => 52.519 [lon] => 13.406 [id] => 1 [pname] => Firstschool [typ] => 0 [s_id] => 32 [fac] => history) 

[1] => Array ( [place_id] => 1 [place] => Berlin [lat] => 52.519 [lon] => 13.406 [id] => 1 [pname] => Secondschool [typ] => 0 [s_id] => 33 [fac] => math)

[2] => Array ( [place_id] => 1 [place] => Berlin [lat] => 52.519 [lon] => 13.406 [id] => 1 [pname] => Secondschool [typ] => 0 [s_id] => 33 [fac] => english)
)

The data is redundant at some points, I need it this way:

Array ( 
  [Berlin] => Array ( [lat] => 52.519 
                      [lon] => 13.406  
                      [schools] => Array([0]=> Firstschool [1]=>Secondschool)
  )

  [OtherCity] => Array ( ... )
)

First, is this okay or exists a better solution? =) Second.. how to split it for the needed result.

I tried it with something like the following code snippet, but it doesn't work as wished.

foreach($viewmodel as $item) { 
   $data[$item['place']][] = $item['pname'];
}

The result is:

Array ( [Berlin] => Array ( [0] => Firstschool [1] => Firstschool [2] => Firstschool ))

NOT so useful. ;)

I hope its understandable what I need. Maybe someone has an nice idea how to solve this problem.

Thanks for your time.

complex857 · Accepted Answer · 2013-02-17 21:26:08Z

1

I think you are on a right path, just need to fill in a little more detail:

$cities = Array (
     Array ( 'place_id' => 1, 'place' => 'Berlin', 'lat' => 52.519, 'lon' => 13.406, 'id' => 1, 'pname' => 'Firstschool', 'typ' => 0, 's_id' => 32, 'fac' => 'history'),
     Array ( 'place_id' => 1, 'place' => 'Berlin', 'lat' => 52.519, 'lon' => 13.406, 'id' => 1, 'pname' => 'Secondschool', 'typ' => 0, 's_id' => 33, 'fac' => 'math'),
     Array ( 'place_id' => 1, 'place' => 'Berlin', 'lat' => 52.519, 'lon' => 13.406, 'id' => 1, 'pname' => 'Secondschool', 'typ' => 0, 's_id' => 33, 'fac' => 'english'),
);

// gather the transformed array in a new array 
$out = array();
foreach ($cities as $city) {
    // the first time we see the place
    if (!isset($out[$city['place']])) {
        // copy over what you want to keep
        $out[$city['place']] = array(
            'lat' => $city['lat'],
            'lon' => $city['lon'],
            'schools' => array($city['pname']),
        );
    } // only add $city['pname'] if we don't have it already
    elseif (!in_array($city['pname'], $out[$city['place']]['schools'])) {
        // we already seen this place, just add to the schools
        $out[$city['place']]['schools'][] = $city['pname'];
    }
}

For the gather faculties too question, use the school names as keys to arrays in the 'schools' key of the top level arrays, populate them like this: (still skipping duplicates):

foreach ($a as $city) {
    if (!isset($out[$city['place']])) {
        $out[$city['place']] = array(
            'lat' => $city['lat'],
            'lon' => $city['lon'],
            'schools' => array($city['pname'] => array($city['fac'])),
        );
    } else {
        // for convenience and readability, introducing some variables
        $schools = &$out[$city['place']]['schools'];
        $pname = $city['pname'];
        $fac = $city['fac'];

        // if we didn't see this school yet, add it with it's faculty
        if (!isset($schools[$pname])) {
            $schools[$pname] = array($fac);
        } // if we did see this school before but the faculty is new, add it under the school's key
        else if (!in_array($fac, $schools[$pname])) { 
            $schools[$pname][] = $fac;
        }
    }
}

edited Feb 17, 2013 at 21:26

answered Feb 17, 2013 at 19:50

complex857

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6 Comments

user2081104 Over a year ago

Wow, thanks. This works. But I have a little question, though. Now in this way, he give me the school for every result, even if this school is already mentioned. In this case, I get secondschool two times. I thought I can stop this with if (!isset($out[$city['place']]['schools'])) , but then, I only get the firstschool and nothing more. =)

complex857 Over a year ago

Oh, i didn't realized that, updated the answer. Actually, there's a lot of different way to go about that, added a pretty straightforward one.

user2081104 Over a year ago

Yeah thanks. Your answer works perfect, too. =) Thanks for all you help. Just as a bonus question, is it possible to add the different lesson types (math, history.. not every school has the same) to the school as a sub array again, so tree dimensions? Or is this a bad idea in terms of working with this array? =)

complex857 Over a year ago

Well, you could certainly make it work adding arrays to the schools key, using the $city['pname'] and an array under that key that would hold the $city['fac'] as the values. But at this point its getting a little hairy for primitives i think (-:

complex857 Over a year ago

@user2081104, I've added an implementation.

|

Youn Elan · Accepted Answer · 2013-02-17 19:49:50Z

0

you are right, you have to iterate through the array some way or another. From the array I have seen, assuming all latitudes and longitudes are the same for all schools, overwriting will not hurt, otherwise, additional logic is needed

foreach($viewmodel as $item) {
  $data[$item['place']['lat']=$item['lat'];
  $data[$item['place']['long']=$item['lon'];
  $data[$item['place']['schools'][]=$item['pname'];
}

answered Feb 17, 2013 at 19:49

Youn Elan

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Comments

David Barker · Accepted Answer · 2013-02-17 19:50:31Z

0

You could map the array using a lambda function if you're using php 5.3+

$output = array();

$sort_schools = function($value, $key)
{
    if ( ! is_array($output[$value['place'])
    {
        $output[$value['place'] = array();
    }

    if ( ! isset($output[$value['place']['lat'] && ! isset($output[$value['place']]['lon'])
    {
        $output[$value['place']]['lat'] = $value['lat'];

        $output[$value['place']]['lon'] = $value['lon'];
    }

    $output[$value['place']]['schools'][] = $value['pname'];
};

array_map($sort_schools, $viewmodel);

Alternatively you could use a similar structure in the lambda function within a foreach loop or an anonymous function.

answered Feb 17, 2013 at 19:50

David Barker

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Comments

Pankrates · Accepted Answer · 2013-02-17 20:05:16Z

0

The following should yield the described expected result

$arr =  array( 
            array(  'place_id'  => 1,  'place'  => 'Berlin',  'lat'  => 52.519,  'lon'  => 13.406,  'id'  => 1,  'pname'  => 'Firstschool',  'typ'  => 0,  's_id'  => 32,  'fac'  => 'history'),
            array(  'place_id'  => 1,  'place'  => 'Berlin',  'lat'  => 52.519,  'lon'  => 13.406,  'id'  => 1,  'pname'  => 'Secondschool',  'typ'  => 0,  's_id'  => 32,  'fac'  => 'history'),
            array(  'place_id'  => 1,  'place'  => 'Berlin',  'lat'  => 52.519,  'lon'  => 13.406,  'id'  => 1,  'pname'  => 'Secondschool',  'typ'  => 0,  's_id'  => 32,  'fac'  => 'history')
            );

$result = array();

foreach($arr as $item) {
    if (array_key_exists($item['place'], $result)) {
        if (!in_array($item['pname'], $result[$item['place']]['schools'])) {
            array_push($result[$item['place']]['schools'], $item['pname']);
        }
    } else {
        $result[$item['place']]['lat'] = $item['lat'];
        $result[$item['place']]['lon'] = $item['lon'];
        $result[$item['place']]['schools'][] = $item['pname'];
    }
}

print_r($result);

Which should output

 Array (
     [Berlin] => Array
     (
         [lat] => 52.519
         [lon] => 13.406
         [schools] => Array
             (
                 [0] => Firstschool
                 [1] => Secondschool
             )

     )
)

answered Feb 17, 2013 at 20:05

Pankrates

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1 Comment

user2081104 Over a year ago

Ha, this works like a charm it seems. I'll test it a little bit and stuff and mark it later a solution for my Problem. Thanks dude.

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