Regex pattern for this string

Question

I have a problem to match some string in fallowing lines:

02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.view.WindowManagerImpl$CompatModeWrapper.addView(WindowManagerImpl.java:153) 
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.view.Window$LocalWindowManager.addView(Window.java:559)
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.app.ActivityThread.handleResumeActivity(ActivityThread.java:2716)
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2151)
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.app.ActivityThread.access$700(ActivityThread.java:140)
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1238)
02-16 12:23:24.046  3068  3068 E AndroidRuntime:    at android.os.Handler.dispatchMessage(Handler.java:99)

And i want to match string between two last '(' ')' chars. I know there is a lot of regex tutorials, but i just cannot get it yet. I need to study more about this

So result of success should be:

WindowManagerImpl.java:153
Window.java:559
ActivityThread.java:2716
ActivityThread.java:2151
and so on

All i know is that there is not always word "java", so I want to take value between last "(" ")"

Thank you all for any clues

Why you need regex? Logcat is TAB delimited IIRC.

leppie
– leppie

2013-02-18 10:13:27 +00:00
Commented Feb 18, 2013 at 10:13 — leppie
– leppie, Commented Feb 18, 2013 at 10:13
What does it have to do with design patterns ?

Florian F.
– Florian F.

2013-02-18 10:13:53 +00:00
Commented Feb 18, 2013 at 10:13 — Florian F.
– Florian F., Commented Feb 18, 2013 at 10:13
What have you tried?

Sebastian Paaske Tørholm
– Sebastian Paaske Tørholm

2013-02-18 10:15:19 +00:00
Commented Feb 18, 2013 at 10:15 — Sebastian Paaske Tørholm
– Sebastian Paaske Tørholm, Commented Feb 18, 2013 at 10:15
You could also simply use Substring and LastIndexOf.

sloth
– sloth

2013-02-18 10:18:13 +00:00
Commented Feb 18, 2013 at 10:18 — sloth
– sloth, Commented Feb 18, 2013 at 10:18

samjudson · Accepted Answer · 2013-02-18 10:16:07Z

2

Assuming there are no other parenthesis in the line then something like this would work:

\([^)]+\)

You could then trim the ( and ) off the ends of the match.

Or group in inner text:

\(([^)]+)\)

And then use match.Groups[1].Value to get value of the inner group.

Update: And @cabecao reminded me, if the text always appears at the end, and there might be other parenthesis then add a "$" at the end to match the end of a line.

\([^)]+\)$

answered Feb 18, 2013 at 10:16

samjudson

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Alex Filipovici · Accepted Answer · 2013-02-18 10:17:12Z

2

You may use:

var matches = Regex.Matches(input, @"(?<=\().*(?=\))");
foreach (Match item in matches)
{
    Console.WriteLine(item.Value);
}

answered Feb 18, 2013 at 10:17

Alex Filipovici

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Bergi · Accepted Answer · 2013-02-18 10:18:43Z

2

This should do it:

(?<=\()[^)]+(?=\)$)

Using lookarounds instead of capturing groups to make extracting the result easier. It will match a group of non-parenthesis characters preceded by one and followed by one at the end of the string.

answered Feb 18, 2013 at 10:18

Bergi

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Adam Adamaszek · Accepted Answer · 2013-02-18 10:16:14Z

1

The simplest I can think of now:

.*\((.*)\)$

answered Feb 18, 2013 at 10:16

Adam Adamaszek

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