JSON Validation and parsing in PHP

Question

I am parsing JSON using the following example php syntax

$carModel = strip_tags($_REQUEST['car']['model']);

The only problem is that some times the "model" array is missing from the provided JSON. When this is the case my php script shuts down when it reaches that line. Can any one recommend a way to check for the model array before parsing so that my php scrip will still run if "model" isn't present.

John Conde · Accepted Answer · 2013-02-19 01:18:47Z

2

Just check to see if it's there. If not assign a default value to it:

$carModel = (isset($_REQUEST['car']['model'])) ? strip_tags($_REQUEST['car']['model']) : '';

answered Feb 19, 2013 at 1:18

John Conde

220k100 gold badges464 silver badges504 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Ben Pearce Over a year ago

Thanks. Is it good practice to add this to every line when parsing JSON?

John Conde Over a year ago

It's good practice for any input that you don't have full control over

jeroen · Accepted Answer · 2013-02-19 01:18:33Z

2

I'm not sure how this is related to json, but if you want to check if a variable exists before you use it, you can do:

if (isset($_REQUEST['car']['model']))
{
  $carModel = strip_tags($_REQUEST['car']['model']);
}

answered Feb 19, 2013 at 1:18

jeroen

91.8k22 gold badges117 silver badges132 bronze badges

Collectives™ on Stack Overflow

JSON Validation and parsing in PHP

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related