Javascript array declaration

Question

What object will this create? I've never seen this declaration before so I'm just wondering.

`myArray([]);
 for(someValue = 0; someValue < someOtherValue; i++)
     myArray.push(something[i]);
`

Thanks for any insight you can give me.

EDIT : I Update the code some more to gime some more info. myArray doesn't seem like a function to me in the code. This is used in an AjaxCall. Some lines after it is used like this

So unless I missed something I don't think it is a function.

Probably an object of type myArray.

Waleed Khan
– Waleed Khan

2013-02-19 15:33:43 +00:00
Commented Feb 19, 2013 at 15:33 — Waleed Khan
– Waleed Khan, Commented Feb 19, 2013 at 15:33
[] is an array literal. What is that myArray function?

Bergi
– Bergi

2013-02-19 15:34:11 +00:00
Commented Feb 19, 2013 at 15:34 — Bergi
– Bergi, Commented Feb 19, 2013 at 15:34
it's a function call with an empty array as an argument

Igor Dymov
– Igor Dymov

2013-02-19 15:34:29 +00:00
Commented Feb 19, 2013 at 15:34 — Igor Dymov
– Igor Dymov, Commented Feb 19, 2013 at 15:34
Exactly what I'm wondering. Looks like an array to me.

Ben Lefebvre
– Ben Lefebvre

2013-02-20 14:40:29 +00:00
Commented Feb 20, 2013 at 14:40 — Ben Lefebvre
– Ben Lefebvre, Commented Feb 20, 2013 at 14:40

David G · Accepted Answer · 2013-02-19 15:40:12Z

3

[] is an empty array literal and it's being passed to a function myArray which accepts an array as an argument. This is not a declaration, it's just a function call. It could be defined like this:

function myArray(array) {
    for (var i = 0; i < 5; i++) {
        array[i] = i;
    }
}

var array = []; // empty array to be filled later

myArray(array);

This fills the array with the numbers from 0 to 4.

edited Feb 19, 2013 at 15:40

answered Feb 19, 2013 at 15:34

David G

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Elliot Bonneville · Accepted Answer · 2013-02-19 15:35:03Z

1

You're calling the function myArray and passing in any empty array literal, which is defined by these: []. What's the myArray function look like?

answered Feb 19, 2013 at 15:35

Elliot Bonneville

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Salman · Accepted Answer · 2013-02-19 15:35:07Z

1

If myArray is a function you are calling then [] will pass an empty array as the first argument to it

Its same as doing

var arr = new Array();
myArray(arr);

answered Feb 19, 2013 at 15:35

Salman

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