convert byte array to uint numeric value

Question

Let's say I have array of bytes

byte[] byteArr = new byte[] { 1, 2, 3, 4, 5 };

I want to convert this array to get regular numeric variable of uint, so result will be

uint result = 12345;

So far all the example I've seen were with bytes, byte I don't need bytes, but numeric value.

Thanks...

Jon Skeet · Accepted Answer · 2013-02-22 16:50:33Z

2

It sounds like you want something like:

uint result = 0;
foreach (var digit in array)
{
    result = result * 10 + digit;
}

Or more fancily, using LINQ:

uint result = array.Aggregate((uint) 0, (curr, digit) => curr * 10 + digit);

answered Feb 22, 2013 at 16:50

Jon Skeet

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5 Comments

inside Over a year ago

Hey John, very important question, why is this works only for numbers until 10? If I will convert it from byte array 1, 2, 3, 4, 5, 6, 7, 8, 9 it will give me result 123456789, but if I will convert it from byte array 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 it will give me 1234567900 please need to know how to fix it?

Jon Skeet Over a year ago

@Stanislav: Well what did you want it to give? 10 isn't a digit. (This is why you really need to give clear requiremenst.)

inside Over a year ago

well, got you right now... now know the mistake, thanks, was just a bit confused

inside Over a year ago

but if you have quick answer on how to parse it if there is number higher than 9 and you can share would be great :)

Jon Skeet Over a year ago

A solution requires a problem. Maybe we should just ignore any values over 9. Maybe we should throw an exception. Maybe we should change it to a random number. Without requirements, it's impossible to suggest an implementation.

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