How to create objects in PHP [duplicate]

Question

I'm having difficulty understanding how to create objects in my script.... i get this error :

PHP Fatal error:  Call to undefined function Object()

My code is like this:

$block = Object();  // error here
$row['x'] = 5;
$row['y'] = 7;
$row['widthx'] = 3;
$row['widthy'] = 3;

for($i = $row['x']; $i < ($row['x'] +  $row['widthx']); $i++){

    if(!is_object($block[$i])){
        $block[$i] = Object();
    }


}

Can some one explain what i'm doing incorrectly?

You are looking for new stdClass() instead of Object(). See also php.net/manual/en/language.oop5.basic.php — mario
– mario, Commented Feb 22, 2013 at 23:00
I tried that method first but i got Call to undefined function stdClass() — Sir
– Sir, Commented Feb 22, 2013 at 23:01
@Dave If you got undefined function it means you forgot the new keyword. $block[$i] = new stdClass() — Michael Berkowski
– Michael Berkowski, Commented Feb 22, 2013 at 23:04

sjdaws · Accepted Answer · 2013-02-22 23:33:04Z

2

In the simplest form, objects are classes.

class coOrds {

    // create a store for coordinates
    private $xy;

    function __contruct() {

        // it's still an array in the end
        $this->xy = array();

    }

    function checkXY($x, $y) {

        // check if xy exists
        return isset($this->xy[$x][$y]);

    }

    function saveXY($x, $y) {

        // check if XY exists
        if ($this->checkXY) {

            // it already exists
            return false;

        } else {

            // save it
            if (!isset($this->xy[$x])) {

                // create x if it doesn't already exist
                $this->xy[$x] = array();

            }

            // create y
            $this->xy[$x][$y] = '';

            // return
            return true;

        }

    }

}

$coords = new coOrds();

$coords->saveXY(4, 5); // true
$coords->saveXY(5, 5); // true
$coords->saveXY(4, 5); // false, already exists

Start reading about them here: http://www.php.net/manual/en/language.oop5.basic.php

edited Feb 22, 2013 at 23:33

answered Feb 22, 2013 at 23:01

sjdaws

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9 Comments

Sir Over a year ago

Hmm not seeing how that would allow me to create a list of objects from a loop =/

sjdaws Over a year ago

I think you need to ask yourself 'why am I trying to create objects from a loop?'. If you don't understand an object, I don't see why you're trying to create them or what purpose they will serve.

Sir Over a year ago

Well i want to loop through them because they hold X and Y co ordinates... it will save loop time if i use loop objects rather than an array. Because i can just check if object[$x] exists - if not then no need to keep checking.. if it was an array i have to check them all to be 100% sure the value don't exist

sjdaws Over a year ago

What you're explaining is an array. You want to check if array[$x] exists. I still don't understand why you're trying to create heaps of objects that offer nothing further than what you get from an array. If you're checking keys, it will only exist once in an array since you can't duplicate keys.

Sir Over a year ago

Because creating arrays like this: $myarray[$x][$y]; to store co ordinates will general alot of Undefined offset warnings so my alternative option was to create objects.

|

Lighthart · Accepted Answer · 2013-02-22 23:03:52Z

0

You need to define classes and instance them as objects:

    class Object {
        private $name;

        __construct($name){
            $this->name=$name
        }

        public function setName($name)
        {
            $this->name = $name;

            return $this;
        }

        public function getName()
        {
            return $this->name;
        }
    }

    $block = $new Object($name);

answered Feb 22, 2013 at 23:03

Lighthart

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