Why does python skip my function?

Question

When I input this:

def tablesUsed():
    "Return which multiplication tables to use"
    tablesUsed = [int(x) for x in input("Please choose which multiplication tables you   wish\nto practice, then type them like this: 2 5 10.\n").split()]

python skips over the function to the next line. What is going on?

Seems you're just defining it, to make it run you need to call it. — Joachim Isaksson
– Joachim Isaksson, Commented Feb 23, 2013 at 11:46
Volatility answered you, But instead of input() use raw_input() — Grijesh Chauhan
– Grijesh Chauhan, Commented Feb 23, 2013 at 11:49
@GrijeshChauhan the OP is probably using Python 3 (although you really can't tell) — Volatility
– Volatility, Commented Feb 23, 2013 at 11:50

Volatility · Accepted Answer · 2013-02-23 11:54:23Z

5

You need to call it.

tablesUsed()

You also might want to actually return the list.

def tablesUsed():
    return [int(x) for x in input("Please choose which multiplication tables you   wish\nto practice, then type them like this: 2 5 10.\n").split()]

Otherwise you can't access the list you made in the function, making it useless.

Also, if you're using Python 2, input() evaluates the input as Python code, and you're more than likely going to get an error. Use raw_input() to return a string. In Python 3 raw_input() was removed and replaced by input()

edited Feb 23, 2013 at 11:54

answered Feb 23, 2013 at 11:46

Volatility

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