osx shell date error

Question

I'm trying to subtract the first day of class (17Feb13 day#47) from the current day (24Feb13 day#55) The command date +%j yields 055, instead of 55 so the math errors...

todayIn=$(date +%j)................= 055

firstDay=(47)..........................= 47

myVal=$(todayIn-firstDay)....= error (expecting 8)

millimoose · Accepted Answer · 2013-02-24 12:00:11Z

1

It seems like it should be enough to just strip the leading zero(es) with:

todayIn=$(date '+%j' | sed -e 's/^0*//')

answered Feb 24, 2013 at 12:00

millimoose

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schwep Over a year ago

Millimoose, Thank you, that was what I needed!

trojanfoe · Accepted Answer · 2013-02-24 12:03:09Z

0

Or use expr:

$ a=$(expr 055 - 5)
$ echo $a
$ 50

answered Feb 24, 2013 at 12:03

trojanfoe

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