Copy values between variables in bash script

Question

How can I copy the numeric value in a variable to another variable in bash script. If this were C, I would do

int a=0;
int b;
a=b;

I am trying to do this:

if [ $countip -gt $totalip ]; 
then
    $countip -eq $srctip # <-- My problem is here!
    echo $srctip
fi

Warwick Masson · Accepted Answer · 2013-02-26 17:27:50Z

32

Just say

countip=$srctip

This is how assignment works in bash. This will set countip to the value of srctip. If you want to assign srctip then just write

srctip=$countip

Based on the comments below this looks like the one you want.

edited Feb 26, 2013 at 17:27

answered Feb 26, 2013 at 17:10

Warwick Masson

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5 Comments

gomesg Over a year ago

Thanks for replying, i`m obtaining allways 0 in $srctip.

Kevin Over a year ago

@gomesg are you trying to assign to srctip? Reverse the variables: srctip=$countip.

gomesg Over a year ago

I`m trying to get the highest value of countip and copy it to $srctip. This is what iàm trying to do do. I am sory i am new to bash script. I was for the last 15 years a telecom tec and now i have to admin an entire linux based lan!

gomesg Over a year ago

for srcip in

cat /var/log/messages | grep "WACSLAW1 CRITICAL INCOMING" | awk '{ print $14 }'|grep -v 192.168.1. |grep -v IN=eth1 |grep -v MAC

;do if (! grep "$srcip" /var/wacstemp/ids.tmp > /dev/null) ; then countip=0 echo $srcip >> /var/wacstemp/ids.tmp else countip=expr $countip + 1 if [ $countip -gt $totalip ]; then countip=$srctip echo $srctip fi fi

pfnuesel Over a year ago

Might be better to update your original post if the problem hasn't been solved yet.

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