pass object through @Html.ActionLink with click

Question

What I'm trying to do is pass the item that was clicked to the controller for editing but the only thing I can pass to the controller is a string.

view:

foreach (MenuItemViewModel menuitem in category.MenuItemList)
{
  <span class="MenuItemTitel">
     @if (IsAdmin)
     {
       <span class="AdminSpan">
          @Html.ActionLink("Edit", "EditPage", "Admin", new { name = menuitem.Title })
       </span>
     }
      @menuitem.Title
  </span> 
}

Controller:

public ActionResult EditPage(MenuItemViewModel MenuItem) {}

Yaakov Ellis · Accepted Answer · 2013-02-26 19:20:24Z

4

The @Html.ActionLink() method will generate a url link to the given Controller/Action. Thus, it can only contain parameters that can be contained in the url of the link. So you cannot pass an object through on the url.

If you need to pass through the reference to an object that is stored on the server, then try setting a parameter of the link to give a reference to the object stored on the server, that can then be retrieved by the action (example, the Id of the menuItem in question).

Parameters in the ActionLink are set through the collection that you passed in as the third item in your function call above. Assuming default routing, this would give an address that looks like /Admin/EditPage/?name=XXX where XXX is the value of menuitem.Title. If you included something else here like itemId = menuitem.Id then it would add this as a query string parameter to the url generated, which would then be accessible to the action that is the target of this link.

edited Feb 26, 2013 at 19:20

answered Feb 26, 2013 at 19:09

Yaakov Ellis

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1 Comment

NNassar Over a year ago

I'm not sure I know what you mean by "setting a parameter of the link to give a reference to the object stored on the server"

Hamish · Accepted Answer · 2016-02-14 13:23:12Z

0

I did pass the object with helpt @Html.Action(). See the code below:

@Html.ActionLink("Lista Valores", "Lista", "RandomName",
new {
    Id = @ViewBag.Id,
    Name = "fdsfsadf",
    LastName = @ViewBag.LastName,
    Breed = @ViewBag.Breed,
    System = ViewBag.sys
}, null)

Controller:

public ActionResult Lista(CharNames character)
{
    return View(character);
}

View:

<p>@Html.LabelFor(x => x.Id) @Model.Id</p>
<p>@Html.LabelFor(x => x.Name) @Model.Name</p>
<p>@Html.LabelFor(x => x.LastName) @Model.LastName</p>
<p>@Html.LabelFor(x => x.Breed) @Model.Breed</p>
<p>@Html.LabelFor(x => x.System) @Model.System</p>

edited Feb 14, 2016 at 13:23

Hamish

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answered Feb 14, 2016 at 13:14

GuiSal

1

Comments

Leon Nilo · Accepted Answer · 2021-04-26 06:03:33Z

0

on the Controller:
[Route("customer/detail")]
public ActionResult Detail(Customer customer)
{
   return View(customer);
}

on the source view:

@model List<AI.Models.Customer>
@{
   ViewBag.Title = "Customer List";
   Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>Customers</h2>
<ul>
  @foreach (var customer in Model)
  {
    <li>@Html.ActionLink(@customer.Name, "detail", "customer", @customer, null)</li>
  }
</ul>

on the target view:
@model AI.Models.Customer
@{
  ViewBag.Title = "Details";
  Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>Customer Name : @Model.Name</h2>

answered Apr 26, 2021 at 6:03

Leon Nilo

1

1 Comment

Muhammad Tariq Over a year ago

Please add relevant information with your code. stackoverflow.com/help/how-to-answer

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