PHP Array count and get element values

Question

I'm pretty new to PHP and programming so I'm having troubles with this thing.

The purpose of the whole situation is to read a column from tab delimited file (already did that), get all different items in it, count them individually and put them in table with

Column1[item value - label], Column2[count].

I have the whole column in 1 dimension array. Now, I want to list all the items there and their counts beside. The problem is, I could have more than 10 different items, even more, so I can't do it manually (name 10 variables and count each) like this:

$arr = array("complete","fail","complete","exit","fail","fail","complete");
function isComplete($value){
    return ($value == "complete") ? true : false;
}

$complete = array_filter($array, 'isComplete');

<tr>
   <td>Complete</td>
   <td><?php echo count($complete)?></td>
</tr>

-- > Complete = 3

I want to avoid manually creating every function for each value because values can differ from file to file.

The number of items in $array can go up to 20+k so I need all automated. Can someone help me with this?

George · Accepted Answer · 2013-02-27 13:59:50Z

2

How about going through the array and placing the counts in another array? ($arrCount)

$arr = array("complete","fail","complete","exit","fail","fail","complete");
$arrCount = Array();

foreach($arr as $value){
    $arrCount[$value] = array_key_exists($value,$arrCount) ? $arrCount[$value]+1 : 1;
    //If this key exists, add 1 to it, else make it equal to 1
}

This would create an array with the keys being the various labels and the value equally to the label total.

print_r output:

Array ( [complete] => 3 [fail] => 3 [exit] => 1 )

edited Feb 27, 2013 at 13:59

answered Feb 27, 2013 at 13:46

George

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2 Comments

Ivan Over a year ago

I'm getting "Notice: Undefined index: complete in.." for each $key

Ivan Over a year ago

Great! Thank you! That's exactly what I wanted to do. I combiened it with @Niels reply with table echo and got the right resultes. Thank you so much!

Niels · Accepted Answer · 2013-02-27 13:46:35Z

0

Psuedo code:

$arr = array("complete","fail","complete","exit","fail","fail","complete");
$counts = array();
foreach($arr => $key as $value)
{
    if(array_key_exists($value, $counts))
    {
        $counts[$value]++;
    }else{
        $counts[$value] = 1;
    }
}
foreach($counts => $key as $value)
{
    echo '<tr>
   <td>' . $key . '</td>
   <td>' . $value . '</td>
</tr>';
}

We are making arrays of the elements in the list. If the item exists, increase otherwise create with value 1. Than loop another time to show to the user the total count of each item.

answered Feb 27, 2013 at 13:46

Niels

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2 Comments

Ivan Over a year ago

Is this a right way of writing it "foreach($counts => $key as $value)"? I'm getting Syntax error.

Ivan Over a year ago

Thank you, I used your second part of code with top answer and it worked the way I wanted ;)

ZolaKt · Accepted Answer · 2013-02-27 13:47:41Z

0

Maybe I'm missing the point, but what is the problem with a normal loop? For example:

function countByValue($array, $value){
    $count  = 0;
    foreach($array as $val){
        if ($val == $value){
            $count++;
        }
    }
    return $count;
}

And call it with

$complete = countByValue($arr, 'complete');

If you want to count them all at once go with F4r-20 answer.

answered Feb 27, 2013 at 13:47

ZolaKt

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