Populate a multidimensional array while looping [closed]

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I have an array declared above the beginning of a for loop as: $array = array();. Now, in the for loop I start inserting values into it. At some point I make one of its index as another array as $array[$j]=array(); And insert some values like, $array[$j][$l] = id; and so on.

Now, when I use print_r($array); inside the loop I get the expected value of the array. But outside the loop this newly created array (2-D) is getting lost and I am getting only a 1-D array as an output.

Can someone please tell me where the problem could lie?

It's likely you're using the same value for $j and thus overriding parts of your array (if I'm understanding the problem correctly). — strager
– strager, Commented Oct 2, 2009 at 20:25
@Strager: Thanks a lot for pointing out the problem. I was not able to find it, may be because i never thought that way. Thanks again! :) — mkamthan
– mkamthan, Commented Oct 2, 2009 at 21:06

Topher Fangio · Accepted Answer · 2009-10-02 20:50:27Z

4

The following code works properly. Perhaps you are switching your variables as strager suggests.

<?php
$array = array();

for ($i = 0; $i < 10; $i+=1) {
    if ($i == 5) {
        $array[$i] = array('value 1', 'value 2');
    } else {
        $array[$i] = $i;
    }
}

print_r($array);
?>

answered Oct 2, 2009 at 20:50

Topher Fangio

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