If I have the string
thisIsSomthing=4891\r\n
thisIsSomthingElse=27398472\r\n
thisIsNumber1=1\r\n
how would I find
thisIsNumber1
and then return 1 using regex
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1Is this string in a file?jlordo– jlordo2013-02-28 01:13:22 +00:00Commented Feb 28, 2013 at 1:13
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Why would you use a regex for that? Also, I think we need a better description of what you want. The way the question is asked, your needs could easily be interpretted in many different ways.jahroy– jahroy2013-02-28 01:24:51 +00:00Commented Feb 28, 2013 at 1:24
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3 Answers
This assumes you really have that posted content in a string, and not in a file. As you're dealing with properties, you should use Properties and not a regex:
String yourString = ...
Properties prop = new Properties();
try {
prop.load(new StringReader(yourString));
String result = prop.getProperty("thisIsNumber1");
System.out.println(result);
} catch (IOException e) {
System.out.println("Error loading properties:");
e.printStackTrace();
}
1 Comment
jahroy
I think this is the best answer.
/thisIsNumber1=(\d+).*/
It'll be in capture group 1.
Comments
String line="thisIsNumber1=1\r\n";
String temp=line.split("\\r?\\n")[0].split("=")[1];
System.out.println("Value="+temp+"*"); // 1* "*" shows nothing is concatenated after
the character in the output
1 Comment
jlordo
If you want that line in a single string it would be
String line = "thisIsNumber1=1\r\n";