How to remove character from string using xslt?

Question

<Scheduled>
 <xsl:value-of select="//RequestParameters/Identifier/DepartureDate">
 </xsl:value-of>
 </Scheduled>

In this xslt code iam getting a last character as 'z' in "//RequestParameters/Identifier/DepartureDate" i want to remove z and please help on this.

snak · Accepted Answer · 2013-02-28 06:42:12Z

3

If the value of //RequestParameters/Identifier/DepartureDate contains 'z' only at the end, you can use substring-before function.

<xsl:value-of select="substring-before(//RequestParameters/Identifier/DepartureDate, 'z')">

edit:

If you want to get the first 10 characters of the value, you can use substring function.

<xsl:value-of select="substring(//RequestParameters/Identifier/DepartureDate, 1, 10)">

edited Feb 28, 2013 at 6:42

answered Feb 28, 2013 at 4:39

snak

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2 Comments

shiva tatikonda Over a year ago

thanks snak. Here DepartureDate is of type date for eg value is 2011-10-16T09:40:00.000Z but i need in output(preserve) only ten characters i.e 2011-10-16.Could you please help on this?

snak Over a year ago

You can use substring function for the purpose. Updated the answer.

Maestro13 · Accepted Answer · 2013-02-28 07:21:47Z

0

In general, you may want to convert an element value in ISO 8601 date format to another format by adding a javascript function to your xslt, and call that function in your Xpath expression. For instance, when you have added a (javascript) function convertToDate that extracts the date part of the input value in the format yyyymmdd, the Xpath expression

convertToDate (//RequestParameters/Identifier/DepartureDate)

will result in a value

20111016

assuming there is only one DepartureDate element in the input, having value

2011-10-16T09:40:00.000Z

answered Feb 28, 2013 at 7:21

Maestro13

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