void Example1( char* ArrayA, unsigned int Length )
{
if( ArrayA == 0 )
{
ArrayA = new char[ Length + 1 ];
// Fill it with 2 - whatever
::memset( ArrayA, 0x02, sizeof( char ) * Length );
ArrayA[ Length ] = '0\n';
}
// Do whatever with ArrayA
// Clean-Up
// Error occurs
delete [ ] ArrayA;
};
void Example2( char* ArrayB, unsigned int Length )
{
bool IsDynamic = false;
if( ArrayB == 0 )
{
ArrayB = new char[ Length + 1 ];
// Fill it with 2 - whatever
::memset( ArrayB, 0x02, sizeof( char ) * Length );
ArrayB[ Length ] = '0\n';
IsDynamic = true;
}
// Do whatever with ArrayA
// Clean-Up
// Have to check...
if( IsDynamic )
delete [ ] ArrayB;
};
int main( void )
{
Example1( "\x01\x02\0x03", 3 ); // Example1 WILL NOT* declare ArrayA as a dynamic array - ERROR (caused by deleting non dynamic array)
Example2( 0, 3 ); // ArrayB will be a dynamic array - OK
Example1( 0, 3 ); // OK
Example2( "\x04\x05\0x06", 3 ); // ArrayB isn't a dynamic array - OK
return ( 0 );
};
The problem occurs when attempting to delete char* ArrayA in function Example1 because ArrayA is not a dynamic array. It will only be a dynamic array if it is equal to zero/null. So, to resolve that I created a similar function - Example2. The only difference is that Example2 has a boolean that checks to see if char* ArrayB is a dynamic array or not.
I know what I am doing is either incorrect or "noobish". So please help me. I will learn from my mistake.
How would you do it?
void Example3( char* ArrayC, unsigned int Length );
std::vector<char>?