how to get array using $.ajax in jquery

Question

I have page getorgname.php which return array so how do i get the array in my jquery page using $.ajax method?

$ds = my_ldap_connect(CHI_LDAP_LOCATION, CHI_LDAP_PORT, CHI_LDAP_USE_TLS);
$groups = get_all_groups($ds, CHI_LDAP_BASE_DN, CHI_LDAP_BIND_DIRECTORY, CHI_LDAP_BIND_PASSWORD);
$sr = @ldap_search($ds, "ou=people,".CHI_LDAP_BASE_DN, "(uid=*)");
$nt = ldap_get_entries( $ds, $sr );
//echo "<pre>";
//print_r($nt);
//echo "</pre>";
foreach( $nt as $each )
{
    if( is_array( $each ) )
    {

        $json[] = trim('"'.$each['o'][0].'"');

    }
}

return $json;

Johan · Accepted Answer · 2013-03-01 15:06:40Z

2

Set the proper json headers to serve json and print the array in json format:

header('Cache-Control: no-cache, must-revalidate');
header('Expires: Mon, 26 Jul 1997 05:00:00 GMT');
header('Content-type: application/json'); 

//create your array here

echo json_encode(array);

Then receive the array on the client side using jQuery:

$.ajax({
   url: 'getorgname.php',
   dataType: 'json',
   success: function(data){
       //the 'data' object contains your array
       //do stuff with it here
   }
});

answered Mar 1, 2013 at 15:06

Johan

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Elias Van Ootegem · Accepted Answer · 2013-03-01 15:43:13Z

1

Without setting the data-type in jQ's $.ajax call, and by simply using the echo construct rather then return, you should be fine. If you start messing with the headers, chances are you'll run into trouble sooner or later:
You can only set the headers if no output has been generated yet, so be weary: either buffer, or keep the header calls at the very top. Just know what you're doing.

In your case just ending in echo json_encode($json); will do the trick:

foreach( $nt as $each )
{
    if( is_array( $each ) )
    {
        $json[] = trim($each['o'][0]);
    }
}
echo json_encode($json);

That's all you need to do, you don't have to format the JSON manually.
Your jQ should look something like this:

$.ajax({
    url: 'yourscript.php',
    data: yourRequestObject,
    success: function(response)
    {
        console.log(response);//this'll be either an array or an object (assoc array's are objects in JS)
    }
});

answered Mar 1, 2013 at 15:43

Elias Van Ootegem

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2 Comments

user400654 Over a year ago

Don't forget dataType: "json" to avoid issues if jQuery fails to detect that it's json and not plain text.

Elias Van Ootegem Over a year ago

@KevinB: Well, 9 out of 10 jQuery's "educated guess" is correct (I haven't seen it go wrong once). That said, I haven't used jQuery in over a year now... :)

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