Sorting array of dicts python?

Question

With the following

Code

arr = [{"name":"joe", "hotdogs":5},{"name":"april", "hotdogs":5},{"name":"ryan", "hot dogs":8}]

How to in python sort the elements of the array such as the dicts are sorted by name?

arr = [{"name":"april", "hotdogs":5},{"name":"joe", "hotdogs":5},{"name":"ryan", "hotdogs":8}]

How to apply some function to sort the dicts in the array?

You have already 17 questions; it is high time you learn how to format questions with markdown. — rds
– rds, Commented Mar 3, 2013 at 17:06
Is that your actual data structure, or a simplified example? — Colonel Panic
– Colonel Panic, Commented Mar 3, 2013 at 17:24

JBernardo · Accepted Answer · 2013-03-03 17:04:17Z

6

Like this:

arr.sort(key=operator.itemgetter('name'))

answered Mar 3, 2013 at 17:04

JBernardo

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1 Comment

Rescommunes Over a year ago

import operator

Steven Graham · Accepted Answer · 2013-03-03 17:39:02Z

1

Have a look at the following web page: http://wiki.python.org/moin/HowTo/Sorting/

answered Mar 3, 2013 at 17:39

Steven Graham

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1 Comment

Dimitrios Mistriotis Over a year ago

Liked this answer as gave also some context.

Colonel Panic · Accepted Answer · 2013-03-03 18:30:52Z

0

How about

>>> import collections
>>> collections.OrderedDict(april=5, joe=5, ryan=8)
OrderedDict([('april', 5), ('joe', 5), ('ryan', 8)]

Or per DSM's comment

>>> collections.OrderedDict([('april', 5), ('joe', 5), ('ryan', 8)])
OrderedDict([('april', 5), ('joe', 5), ('ryan', 8)])

edited Mar 3, 2013 at 18:30

answered Mar 3, 2013 at 17:29

Colonel Panic

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2 Comments

DSM Over a year ago

While OrderedDict does preserve order, it can't be used with that call syntax. For example, try collections.OrderedDict(april=5, ryan=8, joe=5). The problem is that the class gets passed an unordered dictionary of keyword arguments.

Colonel Panic Over a year ago

Lame. Thanks DSM, I didn't know that.

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