how to get parameters from command line in unix script [duplicate]

Question

I have to write script in unix.

When I call it like:

./check -l word1 -c word2,

I need to fetch the word which is used with commands -l and -c from inside script.

@Blender I'm assuming bash shell.

squiguy
– squiguy

2013-03-04 08:34:49 +00:00
Commented Mar 4, 2013 at 8:34 — squiguy
– squiguy, Commented Mar 4, 2013 at 8:34

dogbane · Accepted Answer · 2013-03-04 09:06:43Z

0

Use getopts as shown in the following script:

#!/bin/bash

while getopts l:c: option
do
    case "$option" in
        l) 
           loption="$OPTARG"
           ;;
        c)
           coption="$OPTARG"
           ;;
    esac
done

echo "L is: $loption"
echo "C is: $coption"

answered Mar 4, 2013 at 9:06

dogbane

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