Bash while loop echo content of file as a drop down menu form

Question

I have a file which contains following content. I want to be able to write a while loop and echo HTML form.

10.101.0.169
10.101.0.171
10.101.0.175
10.101.0.177
10.101.0.179
10.101.0.181
10.101.0.185
10.101.0.193

I want some thing like this.



while (file1 has entries)
{ echo "option value=IP address1" }
end

The goal is to publish a HTML form which users can use to select the IP address from drop down menu and click submit and parameters will be passed to a CGI script for further processing.

I am sure someone expert should be able to help me.

Thanks

fedorqui · Accepted Answer · 2013-03-05 09:53:38Z

1

Something like this should work in bash way.

while read line
    echo "option value=$line"
done < file_name

If you want it to be in HTML, could be like

echo "<select name=IP>"
while read line
    echo "<option value=$line>$line</option>"
done < file_name
echo "</select>"

answered Mar 5, 2013 at 9:53

fedorqui

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choroba · Accepted Answer · 2013-03-05 09:57:09Z

0

You can use sed:

#! /bin/bash
{
    echo '<select name="ip">'
    sed -e 's|.*|  <option value="&">&</option>|' file
    echo '</select>'
} > out.html

answered Mar 5, 2013 at 9:57

choroba

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