Exploding array for url

Question

I'm developing a site for analyzing a store's data. I need the url part of my array to look like this:

array(
    'url'       => 'http://some.website.com:8080/SASStoredProcess/do?_username=user-123',
    '_password' => 'passwd',
    '_program'  => '/Utilisateurs/DARTIES3-2012/Mon dossier/analyse_dc',
    'annee'     => '2012',
    'ind'       => 'V',
    '_action'   => 'execute'
);

I currently have this and am struggling to convert it to the desired format:

array(
    'url' => 'url=http://some.website.com:8080/SASStoredProcess/do?_username=user-123&_password=passwd&_program=%2FUtilisateurs%2FDARTIES3-2012%2FMon+dossier%2Fanalyse_dc&annee=2012&ind=V&_action=execute',
    'otherKey' => 'otherValue'
);

Please can somebody help me to convert the URL in the second code block to look like the first code block? Thanks in advance.

look at php.net/manual/en/function.parse-str.php

Galen
– Galen

2013-03-05 10:19:44 +00:00
Commented Mar 5, 2013 at 10:19 — Galen
– Galen, Commented Mar 5, 2013 at 10:19
You shouldnt be passing passwords in the URL

acutesoftware
– acutesoftware

2013-03-05 10:20:05 +00:00
Commented Mar 5, 2013 at 10:20 — acutesoftware
– acutesoftware, Commented Mar 5, 2013 at 10:20
You can do a foreach ...

Mihai Iorga
– Mihai Iorga

2013-03-05 10:20:08 +00:00
Commented Mar 5, 2013 at 10:20 — Mihai Iorga
– Mihai Iorga, Commented Mar 5, 2013 at 10:20
stackoverflow.com/questions/6162912/…

user2166576
– user2166576

2013-03-05 10:22:11 +00:00
Commented Mar 5, 2013 at 10:22 — user2166576
– user2166576, Commented Mar 5, 2013 at 10:22

Raad · Accepted Answer · 2013-03-05 10:42:52Z

2

So this will extract the url in the form you want, as $url:

$myArray = array(
    'url' => 'url=http://some.website.com:8080/SASStoredProcess/do?_username=user-123&_password=passwd&_program=%2FUtilisateurs%2FDARTIES3-2012%2FMon+dossier%2Fanalyse_dc&annee=2012&ind=V&_action=execute',
    'otherKey' => 'otherValue'
);
parse_str($myArray['url']);
echo $url;

You will need to decide where it needs to go next and how you get it there.

answered Mar 5, 2013 at 10:42

Raad

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CSᵠ · Accepted Answer · 2013-03-05 10:28:27Z

2

You might want to use: parse_url() and parse_str() over your $array['url']

answered Mar 5, 2013 at 10:28

CSᵠ

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