Regex Python: Get Page and Subpage from URL

Question

I'm sorry I'm pretty noob with regex since long time.

How can I get from this kind of string /projects/myproject/, the 2 following elements (projects , myproject) ?

Output :

print group1 : 'projects'

print group2 : 'myproject'

Thanks

This might not be a job for regexes, but for existing tools in your language of choice. What language are you using? You probably don't want to use a regex, but rather an existing module that has already been written, tested, and debugged. If you're using PHP, you want the parse_url function. If you're using Perl, you want the URI module. If you're using Ruby, use the URI module. — Andy Lester
– Andy Lester, Commented Mar 6, 2013 at 5:10
I know, but I don't know what Python uses. Point is, there are existing written, tested and debugged tools out there for you. — Andy Lester
– Andy Lester, Commented Mar 6, 2013 at 5:45

dlock · Accepted Answer · 2013-03-06 05:25:30Z

1

my_str = "/projects/myproject/"
matches = re.findall("/(.+?)/(.+)/",my_str)
print matches  #prints ['projects','myproject']

edited Mar 6, 2013 at 5:25

answered Mar 6, 2013 at 5:01

dlock

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7 Comments

socrateisabot Over a year ago

your regex is working, but this is what I get : [('projects', 'targetstuffscholarships/')] 1) The last "/" is still here 2) How can I get an array because it's actually a list in an array Thanks

dlock Over a year ago

matches is an array of strings that the regex matched. Not an array of arrays. And, can you show us the string you are matching against?

socrateisabot Over a year ago

The string is : /projects/targetstuffscholarships/

socrateisabot Over a year ago

I'm not getting an array of array but a list included in an array. The parenthesis in my output means that is actually a list

dlock Over a year ago

matches[0] is what you are after. You can access your matches like matches[0][0] and matches[0][1]

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