Python if statement

Question

print("this program will calculate the area")

input("[Press any key to start]")

width = int(input("enter width"))
if width < 0:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

if width > 1000000:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

height = int(input("Enter Height"))

area = width*height

print("The area is:",area)

Is there a way i can condense the code below for example fit them together so i won't have to write just about the same line of code except the less then and greater then statement twice.

width = int(input("enter width"))
if width < 0:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

if width > 1000000:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

I have tried

width = int(input("enter width"))
if width < 0 and > 10000:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

But i get no love.

I also don't want to type

width = int(input("enter width"))

statement twice if it can be helped.

Thanks Ben

Nice work guys, Ty for your time.

BenniMcBeno
– BenniMcBeno

2013-03-08 00:10:28 +00:00
Commented Mar 8, 2013 at 0:10 — BenniMcBeno
– BenniMcBeno, Commented Mar 8, 2013 at 0:10

Daniel Roseman · Accepted Answer · 2013-03-07 09:45:42Z

7

There are a few ways to do it. The most explicit is this:

if width < 0 or width > 10000:

but my favourite is this:

if not 0 <= width <= 10000:

edited Mar 7, 2013 at 9:45

answered Mar 7, 2013 at 9:34

Daniel Roseman

602k68 gold badges910 silver badges923 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

BenniMcBeno Over a year ago

Really you where all rite so thanks, but this one suited me best :)

mpenkov · Accepted Answer · 2013-03-07 09:35:50Z

3

You need a loop. Otherwise, the user can still enter an invalid value if they are persistent. The while statement combines a loop with a conditional - it keeps looping until the condition is broken.

width = -1
while width < 0 or width > 10000:
    width = int(input("enter width as a positive integer < 10000"))

Your use of the if statement in the original question is syntactically incorrect:

if width < 0 and > 10000:

You want:

if not (0 < width < 1000):
    ask_for_new_input()

or, in a more explicit way:

if width < 0 or width > 1000:
    ask_for_new_input()

answered Mar 7, 2013 at 9:35

mpenkov

22k11 gold badges94 silver badges128 bronze badges

Comments

NPE · Accepted Answer · 2013-03-07 09:34:23Z

0

The

if width < 0 and > 10000:

should read

if width < 0 or width > 10000:

Alternatively:

if not 0 <= width <= 10000:

answered Mar 7, 2013 at 9:34

NPE

503k114 gold badges970 silver badges1k bronze badges

Comments

linbo · Accepted Answer · 2013-03-07 09:35:34Z

0

You miss variable width

if width < 0 or width> 10000:

answered Mar 7, 2013 at 9:35

linbo

2,4313 gold badges23 silver badges45 bronze badges

Comments

Artsiom Rudzenka · Accepted Answer · 2013-03-07 09:57:27Z

0

What if:

print("this program will calculate the area")

res = raw_input("[Press any key to start]")

def get_value(name):
    msg = "enter {0}".format(name)
    pMsg = "please choose a number between 0-1000"
    val = int(input(msg))
    while val not in xrange(1, 1001):
        print pMsg
        val = int(input(msg))
    return val


print("The area is: {0}".format(get_value('width') * get_value('height')))

edited Mar 7, 2013 at 9:57

answered Mar 7, 2013 at 9:44

Artsiom Rudzenka

29.3k5 gold badges36 silver badges53 bronze badges

Comments

Himanshu · Accepted Answer · 2013-03-08 10:04:43Z

0

You want to say

if width < 0 or width > 10000:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

edited Mar 8, 2013 at 10:04

answered Mar 7, 2013 at 9:34

Himanshu

2,4743 gold badges26 silver badges42 bronze badges

1 Comment

eumiro Over a year ago

Nobody wants to say width < 0 or > 10000.

Collectives™ on Stack Overflow

Python if statement

6 Answers 6

1 Comment

Comments

Comments

Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

1 Comment

Comments

Comments

Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related