In Javascript it would be:
var newObject = { 'propertyName' : 'propertyValue' };
newObject.propertyName; // returns "propertyValue"
But the same syntax in Python would create a dictionary, and that's not what I want
new_object = {'propertyName': 'propertyValue'}
new_object.propertyName # raises an AttributeError
obj = type('obj', (object,), {'propertyName' : 'propertyValue'})
there are two kinds of type function uses.
'obj' class that inherits from the object with a 'propertyName' member set to 'propertyValue' ." And what do you know? I was right! I don't think it's too unintuitive.
(): obj = type('obj', (object,), {'propertyName' : 'propertyValue'})()Python 3.3 added the SimpleNamespace class for that exact purpose:
>>> from types import SimpleNamespace
>>> obj = SimpleNamespace(propertyName='propertyValue')
>>> obj
namespace(propertyName='propertyValue')
>>> obj.propertyName
'propertyValue'
In addition to the appropriate constructor to build the object, SimpleNamespace defines __repr__ and __eq__ (documented in 3.4) to behave as expected.
type and intuitive.Peter's answer
obj = lambda: None
obj.propertyName = 'propertyValue'
I don't know if there's a built-in way to do it, but you can always define a class like this:
class InlineClass(object):
def __init__(self, dict):
self.__dict__ = dict
obj = InlineClass({'propertyName' : 'propertyValue'})
I like Smashery's idea, but Python seems content to let you modify classes on your own:
>>> class Inline(object):
... pass
...
>>> obj = Inline()
>>> obj.test = 1
>>> obj.test
1
>>>
Works just fine in Python 2.5 for me. Note that you do have to do this to a class derived from object - it won't work if you change the line to obj = object.
obj = lambda: None, which is bizarre, but will perform the necessary tasks...
SilentGhost had a good answer, but his code actually creates a new object of metaclass type, in other words it creates a class. And classes are objects in Python!
obj = type('obj', (object,), {'propertyName' : 'propertyValue'})
type(obj)
gives
<class 'type'>
To create a new object of a custom or build-in class with dict attributes (aka properties) in one line I'd suggest to just call it:
new_object = type('Foo', (object,), {'name': 'new object'})()
and now
type(new_object)
is
<class '__main__.Foo'>
which means it's an object of class Foo
I hope it helps those who are new to Python.
It is easy in Python to declare a class with an __init__() function that can set up the instance for you, with optional arguments. If you don't specify the arguments you get a blank instance, and if you specify some or all of the arguments you initialize the instance.
I explained it here (my highest-rated answer to date) so I won't retype the explanation. But, if you have questions, ask and I'll answer.
If you just want a generic object whose class doesn't really matter, you can do this:
class Generic(object):
pass
x = Generic()
x.foo = 1
x.bar = 2
x.baz = 3
An obvious extension would be to add an __str__() function that prints something useful.
This trick is nice sometimes when you want a more-convenient dictionary. I find it easier to type x.foo than x["foo"].
Another viable option is to use namedtuple:
from collections import namedtuple
message = namedtuple('Message', ['propertyName'], verbose=True)
messages = [
message('propertyValueOne'),
message('propertyValueTwo')
]
class test:
def __setattr__(self,key,value):
return value
myObj = test()
myObj.mykey = 'abc' # set your property and value
