Send and Decode Object Array via JSON

Question

I have an array of People objects. I'm sending them to PHP but the way to get my objects back in PHP so I can manipulate them seems convoluted. Here's what I have, but it doesn't seem to return anything back to my AJAX Call. Right now I just have 1 Person Object in my array but I want to make sure everything is fine before I advance. In short, when I decode my JSON shouldn't it convert it to an Object in PHP? In the end I want an array of PHP objects that are People

Jquery

var people = new Array();
var person = new Person("Michael", "Jackson", 50);
localStorage.setItem(person.firstName + " " + person.lastName, JSON.stringify(person));

function Person(firstName, lastName, age)
{
    this.firstName=firstName;
    this.lastName=lastName;
    this.age=age;
}

function getStorage(){
    var tempPerson;
    for(var i = 0; i < localStorage.length; i++)
    {
        tempPerson = $.parseJSON(localStorage.getItem(localStorage.key(i)));
        people.push(tempPerson);
    }
}

function getPeople(){
    $.post(
        "people.php",
        {people : people},
        function(data) 
        {
            alert(data);
        }
    );
}

getStorage();
getPeople();

PHP

<?php
$personObj = Array();
$people = $_POST['people'];

for($i = 0; $i < count($people); $i++)
{
    foreach($people[$i] as $person)
    {
        $streamObj = json_decode($person);
    }
}

echo $personObj->$firstName;

John S · Accepted Answer · 2013-03-12 02:17:07Z

2

In addition to making the change suggested by @Even Hahn, you need to change the data you are posting as follows:

$.post(
    "people.php",
    {people : JSON.stringify(people)},
    function(data) 
    {
        alert(data);
    }
);

This way a single name/value pair is posted. The name is "people" and the value is a JSON encoded string of the array of Person objects.

Then when you call the following in the PHP code, you are decoding that JSON encoded string into an array on the PHP side.

$people = json_decode($_POST['people']);

I also see where you assign $personObj to an array, but I don't see where you put anything in the array.

answered Mar 12, 2013 at 2:17

John S

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Comments

Evan Hahn · Accepted Answer · 2013-03-12 01:55:26Z

1

Try moving your JSON decoding in your PHP:

$personObj = Array();
$people = json_decode($_POST['people']);

for($i = 0; $i < count($people); $i++)
{
    foreach($people[$i] as $person)
    {
        $streamObj = $person;
    }
}

echo $personObj->$firstName;

This is because $_POST['people'] is a JSON string which needs to be decoded.

answered Mar 12, 2013 at 1:55

Evan Hahn

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1 Comment

Derp Over a year ago

I tried that and it said it needed a string. People is an array. I'm pushing it into the array at getStorage();

Julian Tanjung · Accepted Answer · 2013-03-12 02:38:18Z

0

Perhaps the PHP codes should be look like this:

<?php
$personObj = Array();
$people = $_POST["people"];

foreach($people as $p)
{
    $val = str_replace("\\","",$p);
    $personObj = json_decode($val);
}

echo $personObj->firstName;
?>

answered Mar 12, 2013 at 2:38

Julian Tanjung

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