Why is my bash script that executes another script not exiting?

Question

I'm calling another script from my bash script like so -- with an ampersand.

OtherScriptThatDoesNotExit &
echo "done"

I see it getting to "done" but I still see my original script running is ps. Any idea why this could be? (Note, I'm running on Puppy Linux)

salezica · Accepted Answer · 2013-03-13 01:23:22Z

3

The script is still waiting on the subprocess you spawned. Use nohup, disown or screen to leave a long running task in the background and get back to your shell.

answered Mar 13, 2013 at 1:23

salezica

77.5k29 gold badges113 silver badges168 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

user1898811 Over a year ago

Additionally, if you do need to wait for the script to finish, you can use 'wait' to pause execution until all jobs have completed.

Edwin Evans Over a year ago

So I just call disown in the line after OtherScriptThatDoesNotExit? Or what are the differences?

salezica Over a year ago

Yes, though nohup is a bit more appropriate for script usage. nohup will redirect output to a file, with disown it'll be gone

Collectives™ on Stack Overflow

Why is my bash script that executes another script not exiting?

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related