MATLAB - Convert Number Character array to Number Integer array/matrix?

If you convert your matrix into a column vector, each character will be positioned in a different row, so that it can be handled independently by str2num. Then reshape back:

result = reshape(str2num(A(:)), size(A))

I don't know why you are converting twice. Just go through both indexes and convert each char and put it in the new matrix.

for i = 1:size(A,1)
    for t = 1:size(A,2)
        result(i,t) = str2num(A(i,t));
    end
end

PS: Preallocating result befoor the loops will increase speed:

result = zeros(size(A))

The matrix result1 is what you want.

Eitan T's answer is probably best. It's cleaner and probably faster. But there are some related indexing issues to point out.

If you know the input characters are all digits, you can use a trick with Unicode character values, using the fact that the characters '0' through '9' are sequential.

result = double(A) - double('0');

Your original code almost works, except you're not using i to index in to the result, so you're rewriting a single row each pass through that outer loop. Use both indexes and the result will get its shape right.

for i = 1:5 %the number of rows in the char array
    s = num2str(A(i,:));
    for t = length(s):-1:1
        result(i,t) = str2num(s(t));
    end
end

That would get you the output you want. But there are some issues that'll crop up later. The num2str() call is superfluous, since the data is already char; you can just remove it. You can just use A(i,t) instead of s. And str2double is generally faster and safer than str2num since str2num calls eval behind the scenes.

But you can also just iterate through every element of a multidimensional array in one loop. This is a more general approach. When you use a single index, Matlab indexes linearly in to the array, regardless of its dimensionality.

result = NaN(size(s));
for i = 1:numel(s)
    result(i) = str2double(s(i));
end